C=(1,9)and D=(7,-7). CD=

Determine the measure of each indicated angle. Show all necessary steps!

Rasek [7]

a)

We know that a 4-sided polygon's angles add up to 360 degrees

so to find x:

360-(69+118+84)=89 degrees

b)

For a 4-sided polygon we also know that the outside angles add up to 360 degree.

so to find p:

360-(100+62+106)=92 degrees

Hope it helps!

3 0

2 years ago

FYI, I don't have many points.

zimovet [89]

Answer:

ok i see that question it would be 3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

One teacher wants to give each student 7 over 9 of a slice of pizza. If the teacher has 7 slices of pizza, then how many student

Anna007 [38]

Total = 7 slices.
1student = 7/9 of a slice.

Total number of students:

$7 \div \dfrac{7}{9}$

$= 7 \times \dfrac{9}{7}$

$= 9$

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Answer: She will be able to hand out to 9 students.
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3 0

3 years ago

Two polygons are similar. The perimeter of the larger polygon is 120 yards and the ratio of the corresponding side lengths is 1/

Kay [80]

Answer:

20 yards

Step-by-step explanation:

Given that:

Two Given polygons are similar :

Ratio of corresponding sides =. 1/6

Perimeter of larger polygon = 120 yards

Perimeter of smaller = p

Since they are similar, and yhe ratio of their sides Given, we use the relation :

(Smaller perimeter / larger perimeter) = (smaller side / larger side)

(p / 120) = (1 /6)

Cross multiply :

6p = 120

p = 120/6

p = 20 yards

4 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

3 years ago