Given:
Polynomials
To find:
Monomial of 2nd degree with leading coefficient 3
Solution:
Monomial is an algebraic expression with only one term.
Option A: 
It is not a monomial because it have 2 terms.
It is not true.
Option B: 
It is not a monomial because it have 2 terms.
It is not true.
Option C: 
It have one term only. So, it is a monomial.
Degree means highest power. So degree = 2
Leading coefficient means the value before variable.
Leading coefficient = 3
It is true.
Option D: 
It have one term only. So, it is a monomial.
Degree means highest power. So degree = 3
It is not true.
Therefore is a monomial of 2nd degree with a leading coefficient of 3.
Answer:
B could be used to show the formula to describe the sentence
Answer:
The error in rounding a number is half of the unit of measure. The number was rounded to the nearest 0.1 unit so the error is half of 0.1 which is 12⋅0.1=0.05
2
1
⋅0.1=0.05. Since 3.7+0.05=3.753.7+0.05=3.75 and 3.7−0.05=3.653.7−0.05=3.65, then the error interval is \boxed{3.65\le x<3.75}.
Step-by-step explanation:
Answer:
19 days
Step-by-step explanation:
305 - 115 = 190
190 ÷ 10 = 19
There is a trig identity called the sum of 2 angles for sin its<span>
sin(a+b)=sin(a)cos(b)+cos(a)(sin(b)
</span>
You will need to use it. So in your question split the 4x in 2 equal parts 2x and 2x
<span>
</span><span>sin(4x)=sin(2x+2x)
</span>Now using the expansion above you will get
<span>sin(2x+2x)=sin(2x)×cos(2x)+cos(2x)×sin(2x)
</span>And it will simplify to
<span><span>2sin(2x)cos(2x)
I hope this helps you! Good luck :)</span></span>
