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2 years ago

11

Alex counted to 2400 by 6's beginning with 6. Matthew counted to 2400 by 4's starting with 4. How many of the numbers counted by

Alex were also counted by Matthew?

1 answer:

kondaur [170]2 years ago

6 0

Answer: 200

Step-by-step explanation:

Number of numbers counted by Alex;

= 2,400 / 6

= 400

Number of numbers counted by Matthew;

= 2,400/4

= 600

Numbers that both of them counted = 600 - 400

= 200

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What is the domain and range of the graph?

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3 years ago

Which are linear pairs? Check all that apply.

boyakko [2]

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Options B, C and D

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3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id

taurus [48]

Answer:

$\boxed{\bf \: \cfrac{13}{5}}$

<u>Or in Decimal:</u>

$\boxed{\bf \: 2.6}$

Step-by-step explanation:

<u>Given expression :-</u>

$\sf \: ( 26 \div 100) \times 10$

<u>Solution :-</u>

$\sf = (26 \div 100 )\times 10$

This arithmetic expression may be rewritten as ;

$\sf = \cfrac{26}{100} \times 10$

Step 1 : <u>Cancel the zero of 10 and one zero of 100</u> :-

$\sf = \cfrac{26}{10 \cancel0} \times 1 \cancel0$

<em>Results to;</em>

$\sf = \: \cfrac{26}{10} \times 1$

$\sf = \: \cfrac{26}{10}$

Step 2: <u>Cancel 26 and 10</u><u> </u><u>by 2</u> :-

$\sf = \cfrac{ \cancel{26}}{ \cancel{10}}$

<em>Results to;</em>

$\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }$

$\sf = \cfrac{13}{5}$

<em>It can also be in Decimal.</em>

That is;

$\sf = 2.6$

Hence, the answer of the expression would be 13/5 or 2.6 .

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

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