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nydimaria [60]
3 years ago
11

Alex counted to 2400 by 6's beginning with 6. Matthew counted to 2400 by 4's starting with 4. How many of the numbers counted by

Alex were also counted by Matthew?
Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer: 200

Step-by-step explanation:

Number of numbers counted by Alex;

= 2,400 / 6

= 400

Number of numbers counted by Matthew;

= 2,400/4

= 600

Numbers that both of them counted = 600 - 400

= 200

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Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

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8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute

P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)

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… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)

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6 0
3 years ago
Can u help me on this pl
VLD [36.1K]

Answer:

B) 9d^8

Step-by-step explanation:

To find the expression equivalent to (3d^4)^2, we must simplify the given expression. This can be done by applying an exponent rule:

(a*b)^x=a^xb^x

In the context of our problem, we would have:

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Simplified, we have:

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3 years ago
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4 0
3 years ago
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