Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample 
= 31.2 pounds .
Step-by-step explanation:
The weights of spawning Chinook salmon in the Columbia river are normally distributed.
Given : The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.
The point estimate for the mean 
weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]
Answer:
-4,790
Step-by-step explanation:
60 x 389 = 23,340
18,550 - 23,340 = -4,790
Answer:
r = 15
Step-by-step explanation:
Volume of a sphere is given by
V = 4/3 pi r^3
4500 pi = 4/3 pi r^3
Divide each side by pi
4500 = 4/3 r^3
Multiply each side by 3/4
3/4 *4500 = 3/4 *4/3 r^3
3375 = r^3
Take the cube root of each side
(3375)^(1/3) = (r^3)^(1/3)
15 = r
Answer:
2/3
Step-by-step explanation:
3x-5=-3
3x=-3+5
3x=2
x=2/3
Answer:
admission price of each parent = $7.5
admission price of each child = $15
Step-by-step explanation:
x = admission price of each parent
y = admission price of each child
Robinson family:
2x + 4y = 75
Moore family:
2x + 3y = 60
2x + 4y = 75 (1)
2x + 3y = 60 (2)
Subtract (2) from (1)
4y - 3y = 75 - 60
y = 15
Substitute y = 15 into (1)
2x + 4y = 75
2x + 4(15) = 75
2x + 60 = 75
2x = 75 - 60
2x = 15
x = 15/2
x = 7.5
