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2 years ago

11

Alex counted to 2400 by 6's beginning with 6. Matthew counted to 2400 by 4's starting with 4. How many of the numbers counted by

Alex were also counted by Matthew?

1 answer:

kondaur [170]2 years ago

6 0

Answer: 200

Step-by-step explanation:

Number of numbers counted by Alex;

= 2,400 / 6

= 400

Number of numbers counted by Matthew;

= 2,400/4

= 600

Numbers that both of them counted = 600 - 400

= 200

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Any answers? No need for an explanation if you want to sure, the answer would be appreciated!

Simora [160]

Yes because 9+4 = 13 and if you plug in the y and x it turns out true

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2 years ago

Surface area of this right prism

Sphinxa [80]

$\qquad\qquad\huge\underline{{\sf Answer}}$

$\textsf{Let's calculate the surface area of given right prism}$

$\textbf{Area of Triangles :}$

$\sf{\dfrac{1}{2}\cdot 16\cdot 12}$

$\sf{8×12}$

$\sf96 \: \: cm {}^{2}$

$\textsf{Since there are two triangles, }$

$\textsf{Area of Triangles = 96 × 2 = 192 cm²}$

$\textbf{Now, calculate the Areas of rectangles :}$

$\textsf{Area - 1 = 12 × 10 = 120 cm²}$

$\textsf{Area - 2 = 16 × 10 = 160 cm²}$

$\textsf{Area - 3 = 20 × 10 = 200 cm²}$

$\textsf{Now add them all :}$

$\textsf{120 + 160 + 200 + 192}$

$\textsf{672 cm²}$

7 0

2 years ago

Read 2 more answers

Which pickle jar deal has the best price per ounce? $3.45 or 14 oz $4.35 for 16 oz $3.29 for 12 oz $4.25 for 15 oz

Allisa [31]

To find the answer divide each money amount by the cost:
3.45/14=<span>0.246428571429
</span>4.35/16=0.271875
3.29/12=0.274166666667
4.25/15=<span>0.283333333333
</span>The pickle jar that has the best deal is 14 oz for $3.45

Hope this helps!

8 0

3 years ago

A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

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3 years ago

What is the answer of the above question in the diagram

natulia [17]

Answer: 1

Order of operations:
add first (2 + 2)
Multiply ( 2 x (4))
Divide ( 8/(8))
= 1

6 0

2 years ago