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VladimirAG [237]
3 years ago
14

All my points to person who has best answer plz make it simpule

Mathematics
2 answers:
bixtya [17]3 years ago
7 0
8x² + 5 = 35
8x² = 35 - 5
8x² = 30
x² = 30/8
x² = 3.75
x = ±1.94  <span>to the nearest hundredth
</span><span>
So x</span>₁ = -1.94 and x₂ = 1.94
Gelneren [198K]3 years ago
4 0
X=1.94
this is the answer because you subtract the 5 on both sides then divide by 8 which would be x^2=3.75, finally take the square root of both sides to get x=1.94 after rounding
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What is the solution to the equation?
slega [8]
First you can add 26 on both sides so you gonna have : 4x - 3x = 16 - 20 + 26 
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i hope this be helpful 
have a nice day 
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2 years ago
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Need some help with this one.
Verizon [17]

Answer:

x² + 4x + 3

Step-by-step explanation:

to find f(g(x)), substitute x = g(x) into f(x)

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3 years ago
Find the area of the shaded region. Round to the nearest tenth.
drek231 [11]

pi·18.6^2·123°/360° - 1/2·18.6^2·SIN(123°) = 226.3

8 0
2 years ago
The Slow Ball Challenge or The Fast Ball Challenge.
cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

Pitches = 7

P(Hit) = 80\%

Win = \$60

Lost = \$10

Fast Ball Challenge

Pitches = 3

P(Hit) = 70\%

Win = \$60

Lost = \$10

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 7 --- pitches

x = 7 --- all hits

p = 80\% = 0.80 --- probability of hit

So, we have:

P(x) =^nC_x * p^x * (1 - p)^{n - x}

P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}

P(7) =1 * 0.80^7 * (1 - 0.80)^0

P(7) =1 * 0.80^7 * 0.20^0

Using a calculator:

P(7) =0.2097152 --- This is the probability that he wins

i.e.

P(Win) =0.2097152

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 -0.2097152

P(Lose) = 0.7902848

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.2097152 * \$60 + 0.7902848 * \$10

Using a calculator, we have:

Expected = \$20.48576

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 3 --- pitches

x = 3 --- all hits

p = 70\% = 0.70 --- probability of hit

So, we have:

P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}

P(3) =1 * 0.70^3 * (1 - 0.70)^0

P(3) =1 * 0.70^3 * 0.30^0

Using a calculator:

P(3) =0.343 --- This is the probability that he wins

i.e.

P(Win) =0.343

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 - 0.343

P(Lose) = 0.657

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.343 * \$60 + 0.657 * \$10

Using a calculator, we have:

Expected = \$27.15

So, we have:

Expected = \$20.48576 -- Slow ball

Expected = \$27.15 --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

5 0
3 years ago
Approximately what is the mean of this set of data?
PIT_PIT [208]
It should be d which is 45
8 0
3 years ago
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