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AnnyKZ [126]
3 years ago
14

Mary has been offered two jobs.Job a has a starting salary of 36,000 and a raise of 1500 every year.Job B has a starting salary

of 29,000 and a raise of 2500 every year .In how many years would Mary’s salary be the same at both companies .What would that salary be?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
5 0

Answer:

Number of year Mary’s salary be the same at both = 7 year

Equal salary amount =  46,500

Step-by-step explanation:

Given:

Starting salary in job A = 36,000

Gain per year in job A = 1,500

Starting salary in job B = 29,000

Gain per year in job B = 2,500

Find:

Number of year Mary’s salary be the same at both = ?

Equal salary amount = ?

Computation:

Assume : in x year salary from job A is equal to salary from job B

Salary from job A in x year = 36,000 + 1,500 x .........Eq1

Salary from job B in x year = 29,000 + 2,500 x .........Eq2

From Eq1 and Eq2

36,000 + 1,500 x = 29,000 + 2,500 x

7,000 = 1,000 x

x = 7 Year

Number of year Mary’s salary be the same at both = 7 year

From Eq1....

Equal salary amount =  36,000 + 1,500(7)

Equal salary amount =  36,000 + 10,500

Equal salary amount =  46,500

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