If you mean the industrialized apple juice then yes. Even though there are several different compounds and some of them aren't actually dissolved in the liquid, since you can't actually distinguish between them using only your eyes and they do no separate naturally it is actually a homogeneous mixture.
Answer:
the answer should be A. the sum of all forces acting on an object
Explanation:
Answer:
71.372 g or 0.7 moles
Explanation:
We are given;
- Moles of Aluminium is 1.40 mol
- Moles of Oxygen 1.35 mol
We are required to determine the theoretical yield of Aluminium oxide
The equation for the reaction between Aluminium and Oxygen is given by;
4Al(s) + 3O₂(g) → 2Al₂O₃(s)
From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.
Therefore;
1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen
1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium
Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.
4 moles of aluminium reacts to generate 2 moles aluminium oxide.
Therefore;
Mole ratio Al : Al₂O₃ is 4 : 2
Thus;
Moles of Al₂O₃ = Moles of Al × 0.5
= 1.4 moles × 0.5
= 0.7 moles
But; 1 mole of Al₂O₃ = 101.96 g/mol
Thus;
Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol
= 71.372 g
<span>You can find
the number of moles in equilibrium if you got the chemical reaction correctly. Make
sure that you got the exact chemical formula of the substance that is reacting
and the yielded product. If you got them, balance the chemical reaction. If the
chemical reaction is balanced, the system is in equilibrium. You can find the
number of moles in equilibrium at the coefficients of the chemical substances
you are balancing. For example, N2 + 3H2 -> 2NH3. The number of moles of N2
is 1, H2 is 3 and NH3 is 2.</span>
Answer:
the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.
Explanation:
Hope this helps. :)
