<u>Answer:</u>
The correct answer option is 1.6 atm.
<u>Explanation:</u>
We know that there is a sample gas which has a volume of 2.4 L with a pressure 1.2 atm and we are to find the pressure of the same gas sample if its volume is reduced to 1.8 L at a constant temperature.
We will apply the Boyle's law here which states that the "pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature".
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Substituting the values in the formula to get:
Therefore, the pressure of the same gas sample will be 1.6 atm if the volume is reduced to 1.8 L at a constant temperature.
When you rub an inflated balloon on your head and it makes your hair stand up, the force that makes the hair stand up is known as static electricity.
When the balloon is rubbed on the head, electrons from the hair atoms move into the balloon, thus making the balloon to be negatively charged and the hair positively charged due to loss of electrons.
Unlike charges attracts. Thus, when you try to pull the balloon away slowly, the positively charged hair and the negatively charged balloon will attract each other and this is usually what makes the hair stand up.
More on static electricity can be found here: brainly.com/question/24160155
Answer:
0.826 g/cm³
Explanation:
density = mass/volume
density = 715 g/866 cm³
density = 0.82564 g/cm³
Rounded to 3 significant figures: 0.826 g/cm³
Answer:
P₂ = 5000 KPa
Explanation:
Given data:
Initial volume = 2.00 L
Initial pressure = 50.0 KPa
Final volume = 20.0 mL (20/1000=0.02 L)
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
50.0 KPa × 2.00L = P₂ × 0.02 L
P₂ = 100 KPa. L/0.02 L
P₂ = 5000 KPa
Answer:
c. -1020.9 kJ
Explanation:
4Fe (s) + 3 O₂ (g) --> 2 Fe₂O₃(s) ΔH = -826.0 kJ/mol.
atomic weight of iron = 56
69.03 g = 69.03 / 56
= 1.23268 moles
Heat released by 1.23268 moles
= 1.23268 x 826.0
= -1020.9 kJ .
