Answer:
D. Hund's rule
Explanation:
Not sure, but I would go with Hund's since it talks about filing electrons in each orbital before you can pair them up. The reason sulfur has lower ionization is because it has one set of paired electrons which makes the orbital unstable whereas phosphorus has 3 unpaired e's which means it is more stable. Thus it is easier to remove electron from sulfur hence lower ionization energy.
Answer:
See explanation
Explanation:
The ionic radius of metal M decreases as the charge on the metal M increases. The ionic radius is generally defined as the distance between the nucleus and the outermost electron of the ion. Hence, ionic radius becomes much lesser as the magnitude of the positive charge increases.
It is obvious from the various formulae of metal chlorides in the question that the metal forms cations M^2+, M^3+ and M^4+ respectively. The order of decreasing ionic radius of the compounds is;
MX2 > MX3 > MX4
Technically it's grp 1 elements...the answer is ribidium Rb
Active transport is the moving of molecules across the membrane of the cell against the concentration gradient with the use of ATP.
Low to high concentration. Concentration gradient is the diffusion (movement of molecules from regions of low concentration) from high to low with the gradient. Active transport is from low to high, against the gradient.
Answer:
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Explanation:
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