What is an equation of the line that passes through the point (-6, -4) and is

Mathematics

1 answer:

suter [353]3 years ago

7 0

X + 6y = 12

6y = -x+ 12

y = -1/6x + 2

the equation of the line is: y+ 4 = -1/6 (x + 6)

You might be interested in

PLEASE HELP! WILL MARK BRAINLIEST!! :D

netineya [11]

Hope this helps

Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.

6 0

3 years ago

How to work out Pythagoras Theoram

Vlad [161]

The Pythagorean Theorem works only with right angle triangles. There are three sides: Side A, Side B, and the hypotenuse.

The formula for the Pythagorean Theorem is: a^2 + b^2 = c^2

To find the answer (without the exponent), you should find the square root.

Now that we have the formula, let's apply it to a triangle:

90^2 + 95^2 = c^2 =

8100 + 9025 = 17125

Square root = 130.86252328302

130.86252328302 is the exact measure of the hypotenuse.

I hope this helped!

Please mark brainliest :)

Have an amaing day!

7 0

3 years ago

Explain the advantages and disadvantages of a non-linear rate structure.<br>Please, help!

zhannawk [14.2K]

Answer:

advantage: it uses memory very efficiently than linear data structures

disadvantages: Non - linear data structures are quite hard to understand and implement than linear data structures

8 0

2 years ago

How to find instantaneous rate of change algebraically?

frosja888 [35]

You use (y2-y1)/(x2-x1) so if you have two points (ex: (1,2) and (2,4)), plug in those number into the formula
(4-2)/(2-1) = 2/1 = 2 so the slope (or instantaneous rate of change) is 2 for those two points<span />

3 0

4 years ago

The back of Tom's property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing for

ICE Princess25 [194]

Answer:

76,050 ft²

Step-by-step explanation:

If the area must be rectangular, let L be the length of the side opposite to the creek, and S be the length of the remaining two sides.

The perimeter of the fencing and the area of the pasture are:

$780 = L+2S\\A= LS\\\\L=780-2S\\A=-2S^2+780S$