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erastovalidia [21]
4 years ago
15

Mind if I get some help?

Mathematics
1 answer:
STALIN [3.7K]4 years ago
3 0
I may be late but I can still help.
The MAD should be 9.

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It's p = 6/(x+a).

Multiply both sides by p to get 6 = p(x+a), then divide both sides by (x+a) to get 6/(x+a) = p.
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3.In 1995, the Educational Testing Service in Princeton, New Jersey (which administers SAT exam) re-centered the scores so that
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Answer:

38.22% probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they score between 900 and 1,100, or they score outside this range. The probability of a student scoring between 900 and 1,100 is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

About 40 percent of these students’ scores were between 900 and 1,100.

This means that p = 0.4.

a)Based on this estimate, what is the probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100?

This is P(X < 4) when n = 10. So

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0060

P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403

P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0060 + 0.0403 + 0.1209 + 0.2150 = 0.3822

38.22% probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100

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3 years ago
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(02.01 LC)
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Answer:

B. Number the students on the school roster. Use a table of random numbers to choose 160  students from this roster for the survey.

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