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2 years ago

I'm lazzzzzzzzy pls answer asap

Mathematics

2 answers:

elena-s [515]2 years ago

8 0

The second one because you times the exponents together

Lemur [1.5K]2 years ago

4 0

You add the exponents

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What is division story problem where the dividend is a three-digit number and the divisor is a single digit.

nasty-shy [4]

Answer:

dddddddddv

Step-by-step explanation:

8 0

2 years ago

Your friend comes from a large family. This list shows the ages of all of the children in her family. What is the median age of

Lyrx [107]

Answer:

It is 11 and 4/7 I am pretty sure hope I helped!

5 0

2 years ago

You meet with the financial aid office to discuss your costs for attending MGA next semester. Tuition is $113.67 per credit hour

jenyasd209 [6]

Answer:

$1615.05

Step-by-step explanation:

First the cost. We know that tuition per credit hour is 113.67 and there is a flat fee of 660. This can be represented by 113.67h + 660, where h is equal to the number of credit hours.

Next, the amount paid. There are two constants of 350 and 400 already there. We can represent the remaining amount that needs to be paid by another variable, x.

Now, the cost needs to be equal to the amount you pay. We can replace h with 15 for 15 hours and solve for x.

113.67h + 660 = 350 + 400 + x

113.67(15) + 660 = 350 + 400 + x

1705.05 + 660 = 750 + x

2365.05 = 750 + x

1615.05 = x

3 0

2 years ago

DFG and JKL are complementary angles. M DFG = x+5 and m JKL=x-9. The measure of DFG is ___, and the measure of JKL is ___.

jeyben [28]

Answer:

Step-by-step explanation:

the sum of complementary angles = 90°, hence

x + 5 + x - 9 = 90

2x - 4 = 90 ( add 4 to both sides )

2x = 94 ( divide both sides by 2 )

x = 47

Thus ∠DFG = 47 + 5 = 52° and ∠JKL = 47 - 9 = 38°

6 0

3 years ago

Read 2 more answers

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

2 years ago