Answer:
- % Cobalt (II) Nitrate = 30.62%
Explanation:
To calculate mass percent, first we need to <u>calculate the total mass of the mixture</u>:
- Mass Water ⇒ 0.350 kg Water = 350 g water
- Mass Ammonia⇒We use ammonia's molar mass⇒5.4 mol * 17 g/mol = 91.8 g
- Mass cobalt (II) nitrate ⇒ 195.0 g
Total Mass = Mass Water + Mass Ammonia + Mass Cobalt Nitrate
- Total Mass = 350 g+ 91.8 g+ 195 g = 636.8 g
To calculate each component's mass percent, we divide its mass by the total mass and multiply by 100:
- % Water ⇒ 350/636.8 * 100% = 54.96%
- % Ammonia ⇒ 91.8/636.8 * 100% = 0.14%
- % Cobalt (II) Nitrate ⇒ 195/636.8 * 100% = 30.62%
Since the pH is a logarithmic scale each increase and or decrease in H+ concentration, changes the pH by 10 fold or 10x the amount. In this case stomach acid is 10x more acidic than lemon juice.
Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points.
Answer:
The boiling point of water at 550 torr will be 91 °C or 364 Kelvin
Explanation:
Step 1: Data given
Pressure = 550 torr
The heat of vaporization of water is 40.7 kJ/mol.
Step 2: Calculate boiling point
⇒ We'll use the Clausius-Clapeyron equation
ln(P2/P1) = (ΔHvap/R)*(1/T1-1/T2)
ln(P2/P1) = (40.7*10^3 / 8.314)*(1/T1 - 1/T2)
⇒ with P1 = 760 torr = 1 atm
⇒ with P2 = 550 torr
⇒ with T1 = the boiling point of water at 760 torr = 373.15 Kelvin
⇒ with T2 = the boiling point of water at 550 torr = TO BE DETERMINED
ln(550/760) = 4895.4*(1/373.15 - 1/T2)
-0.3234 = 13.119 - 4895.4/T2
-13.4424= -4895.4/T2
T2 = 364.2 Kelvin = 91 °C
The boiling point of water at 550 torr will be 91 °C or 364 Kelvin
Answer:
hy do C-C bonds and C-H bonds have high potential energy levels? ... electronegativity so the electrons in the covalent bond are equally shared. Term. Which functional groups are commonly found on a carbohydrate? ... few organisms have the specific enzymes needed to break the bond in the B-form ...
Explanation: