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anzhelika [568]
3 years ago
10

Asap worth 20 points

Chemistry
1 answer:
Olegator [25]3 years ago
5 0
You forgot to attach the question…
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Its right

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Can anyone check my chemistry answers?
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I check all of them. most of them correct but one

in question 6, the answer is the third choice. remember to find the neutrons, you take the atomic mass minus the atomic number. 38 - 18= 20
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3 years ago
C2H5OH( l) + 3O2( g) → 2CO2( g) + 3H2O( l); Δ H = –1.37 × 103 kJ Consider the following propositions: I. The reaction is endothe
Svetlanka [38]

Answer:

II. The reaction is exothermic.

III. The enthalpy term would be different if the water formed was gaseous.

Explanation:

For the reaction:

C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(l)

The  ΔH is -1.37×10³ kJ. As the change in enthalpy is <0,<em> II. The reaction is exothermic.</em>

The ΔH formation of a compound is different if the chemical is in liquid or gaseous phase. For that reason: <em>III. The enthalpy term would be different if the water formed was gaseous.</em>

<em></em>

I hope it helps!

3 0
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