100 PIONTSSSS PLZ HELP Draw the correct structural formula for the following molecules

If a man has a mass of 83 kilograms on Earth, what will the force of gravity on his body be on the moon?

VladimirAG [237]

The answer is (A.) 135.6 N

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Here is the formula you will need to answer the question.

Formula:
Force(N) = Mass(kg) x Acceleration(m/s²)
or... F(N) = m(kg) x a(m/s²)

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We need to be certain of the information presented. The problem says the man has a "Mass" of 83 kilograms on Earth. If a man has a Mass of 83 kilograms on Earth, he has a mass of 83 kilograms everywhere. The mass for this problem (even on the moon) is 83.

Mass(kg): 83

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To find the acceleration of object on other planets, moons, ect, you'll need to search the internet or ask a teacher. There are ways to calculate this, but the problem didn't supply the necessary information to do so.

Acceleration: 1.625 m/s²

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Now just plug the information into the formula.

F(N) = m(kg) x a(m/s²)

N = 83 x 1.625
N= 135.875

When considering that there could be a slighty more accurate number for acceleration, it can be concluded that the best answer is (A.)

3 0

4 years ago

Which element(s) are not balanced in this equation ?

Alekssandra [29.7K]

Only the Fe is unbalanced.
:)

3 0

3 years ago

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How is a Mixture different from a Compound 30 points

barxatty [35]

Answer:

A substance that is comprised of more than one kind of atom reinforced together. Blend: A mix of at least two components or mixes that have not responded to bond together; each part in the combination holds its own properties.

Explanation:

3 0

3 years ago

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Explain fajan's rule

Natalka [10]

Fajans' Rules are used to predict whether a chemical bond will be covalent or ionic.
This depends on: 
- the charge on the cation 
- the size of the cation 
- the size of the anion

7 0

3 years ago

At room temperature, the surface tension of water is 72.0 mJ·m–2. What is the energy required to change a spherical drop of wate

Keith_Richards [23]

It is given that the surface area of sphere is 4 π r² and its volume is (4/3 π r³)
With a diameter of 1.2 mm you have a radius of 0.6 mm so the surface area about 4.5 mm² and the volume is about 0.9 mm³
The total surface energy of the original droplet is (4.5 x 10⁻⁶ m x 72) = 3.24 x 10⁻⁴mJ
The five smaller droplets need to have the same volume as the original so:
5 V = 0.9 mm³ so the volume of smaller sphere will equal 0.18 mm³
Since this smaller volume still have volume (4/3 π r³) so r = 0.35 mm
Each of the smaller droplets has a surface are = 1.54 mm²
The surface energy of the 5 smaller droplet is then (5 x 1.54 x 10⁻⁶ m x 72) = 5.54 x 10⁻⁴ mJ
From this radius the surface energy of all smaller droplets is 5.54 x 10⁻⁴ and the difference in energy is (5.54 x 10⁻⁴) - (3.24 x 10⁻⁴) = 2.3 x 10⁻⁴ mJ
Therefore we need about 2.3 x 10⁻⁴ mJ of energy to change a spherical droplet of water of diameter 1.2 mm into 5 identical smaller droplets

5 0

3 years ago