Fungi have eukaryotic cells (large cells with a nucleus), like animals and plants True or false?
1 answer:
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<span><u><em>Answer:</em></u>
The compound ammonia given by fish is alkaline
<u><em>Explanation:</em></u>
<u>We can classify elements/compounds based on their pH values into three types:</u>
<u>acids:</u> these are compounds having pH value lower than 7
<u>neutral:</u> these are compounds having pH value equal to 7
<u>alkalies:</u> these are compounds having pH values higher than 7
This is shown in the attached image
We are given that the pH of the compound ammonia generated by the fish is above 7.
According to the above explanation, compound ammonia would be an alkaline compound.
Hope this helps :)</span>
The compound ammonia given by fish is alkaline
<u><em>Explanation:</em></u>
<u>We can classify elements/compounds based on their pH values into three types:</u>
<u>acids:</u> these are compounds having pH value lower than 7
<u>neutral:</u> these are compounds having pH value equal to 7
<u>alkalies:</u> these are compounds having pH values higher than 7
This is shown in the attached image
We are given that the pH of the compound ammonia generated by the fish is above 7.
According to the above explanation, compound ammonia would be an alkaline compound.
Hope this helps :)</span>
Explanation:
As it is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.
Hence, putting these values into the above formula as follows.
Molarity =
0.10 M =
no. of moles = 0.001 mol
As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.
No. of moles =
0.001 mol =
mass = 0.06152 g
Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.
0.24 moles of oxygen must be placed in a 3.00 L container to exert a pressure of 2.00 atm at 25.0°C.
The variables given are Pressure, volume and temperature.
Explanation:
Given:
P = 2 atm
V = 3 litres
T = 25 degrees or 298.15 K by using the formula 25 + 273.17 = K
R = 0.082057 L atm/ mole K
n (number of moles) = ?
The equation used is of Ideal Gas law:
PV = nRT
n =
Putting the values given for oxygen gas in the Ideal gas equation, we get
n =
= 0.24
Thus, from the calculation using Ideal Gas law it is found that 0.24 moles of oxygen must be placed in a container.
Ideal gas law equation is used as it tells the relation between temperature, pressure and volume of the gas.