Ask question

Ask question

All categories

3 years ago

12

A square has an apothem measuring 2.5 cm and a perimeter of 20 cm. What is the area of the square, rounded to the nearest square

centimeter?
A. 13 cm2
B.25 cm2
C.50 cm2
D.100 cm2

2 answers:

Ilia_Sergeevich [38]3 years ago

6 0

The apothem of a square is equal to half its side length. Therefore, the square has a side length of 5. The area of a square equals the s^2. Therefore, the area of the square is 5^2=25. (B)

dezoksy [38]3 years ago

3 0

Answer:

B. $25\text{ cm}^2$

Step-by-step explanation:

We have been given that a square has an apothem measuring 2.5 cm and a perimeter of 20 cm.

To find the area of square with given apothem we will use formula:

$\text{Area of square}=\frac{a*p}{2}$ , where,

$a=\text{Apothem of the square}$ ,

$p=\text{Perimeter of the square}$ .

Upon substituting our given values in above formula we will get,

$\text{Area of square}=\frac{2.5\text{ cm}\times 20\text{ cm}}{2}$

$\text{Area of square}=2.5\text{ cm}\times 10\text{ cm}$

$\text{Area of square}=25\text{ cm}^2$

Therefore, the area of our given square will be 25 square cm and option B is the correct choice.

You might be interested in

In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.

Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

$\bar x = A + \frac{\sum fd}{\sum f}$

Where $\bar x$ is the mean

A is the assumed mean

From the given information,

$\bar x = 80$

$A = 60$

$\sum f = 40$

Putting the parameters into the equation, we get

$80 = 60 + \frac{\sum fd}{40}$

$80-60 = \frac{\sum fd}{40}$

$20 = \frac{\sum fd}{40}$

$\sum fd = 20 \times 40$

$\sum fd = 800$

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

#SPJ1

8 0

2 years ago

Marianna [84]

Answer:

B. {16, 19, 20}

Step-by-step explanation:

The <em>triangle inequality</em> requires for any sides a, b, c you must have ...

a + b > c

b + c > a

c + a > b

The net result of those requirements are ...

the sum of the two shortest sides must be greater than the longest side
the length of the third side lies between the difference and sum of the other two sides

__

If we look at the offered side length choices, we see ...

A: 8+11 = 19 . . . not > 19; not a triangle

B: 16+19 = 35 > 20; could be a triangle

C: 3+4 = 7 . . . not > 8; not a triangle

D: 5+5 = 10 . . . not > 11; not a triangle

The side lengths {16, 19, 20} could represent the sides of a triangle.

_____

<em>Additional comment</em>

The version of triangle inequality shown above ensures that a triangle will have non-zero area.

The alternative version of the triangle inequality uses ≥ instead of >. Triangles where a+b=c will look like a line segment--they will have zero area. Many authors disallow this case. (If it were allowed, then {8, 11, 19} would also be a "triangle.")

4 0

2 years ago

At a local store you find the following prices listed: Tape 2 rolls for $1.28 Notepads 3 pads for .87 Highlighters 1 for 1.59 Pe

Serhud [2]

Divide 1.28 by 2 answer .64 notepads divide by 3. u get .29 each so add .29 twice. u get .58 add 1.59 twice. u get 3.18. pens 1.98. add .64 + .58 + 3.18 + 1.98= 6.38 so answer is A

3 0

2 years ago

Help please rn help

aksik [14]

Area of the large semicircle

$= \pi{r}^{2} \div 2$

$= \frac{22}{7} \times 12 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times12 \times 12$

$= \frac{11}{7} \times 144$

$= 226.28$

Area of the small semicircle

$= \pi {r}^{2} \div 2$

$= \frac{22}{7} \times 6 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times 6 \times 6$

$= \frac{11}{7} \times 36$

$= 56.57$

Area of the figure

$= 226.28 - 56.57$

$= 169.71 {cm}^{2}$

8 0

3 years ago

Evaluate 5x when x =8

andrey2020 [161]

Answer:

:( help me on my question

Step-by-step explanation:

4 0

2 years ago