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pochemuha
3 years ago
12

A square has an apothem measuring 2.5 cm and a perimeter of 20 cm. What is the area of the square, rounded to the nearest square

centimeter?
A. 13 cm2
B.25 cm2
C.50 cm2
D.100 cm2
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0
The apothem of a square is equal to half its side length. Therefore, the square has a side length of 5. The area of a square equals the s^2. Therefore, the area of the square is 5^2=25. (B)
dezoksy [38]3 years ago
3 0

Answer:

B. 25\text{ cm}^2

Step-by-step explanation:

We have been given that a square has an apothem measuring 2.5 cm and a perimeter of 20 cm.

To find the area of square with given apothem we will use formula:

\text{Area of square}=\frac{a*p}{2}, where,

a=\text{Apothem of the square},

p=\text{Perimeter of the square}.

Upon substituting our given values in above formula we will get,

\text{Area of square}=\frac{2.5\text{ cm}\times 20\text{ cm}}{2}

\text{Area of square}=2.5\text{ cm}\times 10\text{ cm}

\text{Area of square}=25\text{ cm}^2

Therefore, the area of our given square will be 25 square cm and option B is the correct choice.

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In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.​
Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

\bar x = A + \frac{\sum fd}{\sum f}

Where \bar x is the mean

A is the assumed mean

From the given information,

\bar x = 80

A = 60

\sum f = 40

Putting the parameters into the equation, we get

80 = 60 + \frac{\sum fd}{40}

80-60 = \frac{\sum fd}{40}

20 = \frac{\sum fd}{40}

\sum fd = 20 \times 40

\sum fd = 800

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

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8 0
2 years ago
1
Marianna [84]

Answer:

  B. {16, 19, 20}

Step-by-step explanation:

The <em>triangle inequality</em> requires for any sides a, b, c you must have ...

  a + b > c

  b + c > a

  c + a > b

The net result of those requirements are ...

  • the sum of the two shortest sides must be greater than the longest side
  • the length of the third side lies between the difference and sum of the other two sides

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If we look at the offered side length choices, we see ...

  A: 8+11 = 19 . . . not > 19; not a triangle

  B: 16+19 = 35 > 20; could be a triangle

  C: 3+4 = 7 . . . not > 8; not a triangle

  D: 5+5 = 10 . . . not > 11; not a triangle

The side lengths {16, 19, 20} could represent the sides of a triangle.

_____

<em>Additional comment</em>

The version of triangle inequality shown above ensures that a triangle will have non-zero area.

The alternative version of the triangle inequality uses ≥ instead of >. Triangles where a+b=c will look like a line segment--they will have zero area. Many authors disallow this case. (If it were allowed, then {8, 11, 19} would also be a "triangle.")

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At a local store you find the following prices listed: Tape 2 rolls for $1.28 Notepads 3 pads for .87 Highlighters 1 for 1.59 Pe
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2 years ago
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aksik [14]

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= \pi{r}^{2}  \div 2

=  \frac{22}{7}  \times 12 {}^{2}  \times  \frac{1}{2}

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=  \frac{22}{7}  \times 6 {}^{2}  \times  \frac{1}{2}

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andrey2020 [161]

Answer:

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