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vodka [1.7K]
3 years ago
11

A set of 5 numbers has a mode of 12 a median of 11 a mean of 10 what could the numbers be?

Mathematics
2 answers:
shusha [124]3 years ago
8 0
A possible answer is 6, 9, 11, 12, and 12. Hope I helped (:
BabaBlast [244]3 years ago
4 0
The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.

The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}

Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}

Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15

So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number. 

So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
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levacccp [35]

Answer:

The hikers are 5.9 miles apart.

Step-by-step explanation:

Let O represents the base camp,

Suppose after walking 3.5 miles west, first hiker's position is A, then after going 1.5 miles north from A his final position is B,

Similarly, after walking 2 miles east, second hiker's position is C then going towards 0.5 miles south his final position is D.

By making the diagram of this situation,

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In triangle BD'D,

BD' = AB + AD' = 1.5 + 0.5 = 2 miles,

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By Pythagoras theorem,

BD^2 = BD'^2 + DD'^2

BD = \sqrt{2^2 + 5.5^2}=\sqrt{4+30.25}=\sqrt{34.25}\approx 5.9

Hence, the hikers are 5.9 miles apart.

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3 years ago
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Answer:

26

Step-by-step explanation:

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Answer:

About 20.8 minutes

Step-by-step explanation:

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48

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Take these two ratios and set them equal to each other.

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