What subscripts are needed to complete the formula unit Li_N_?

1 answer:

3 0

In this problem we need to obtain a molecule with a neutral charge that also satisfies the noble gas configuration. Lithium (Li) is a group 1 metal so it needs to lose an electron to achieve noble gas configuration. The loss of an electron will give it a (+1) charge. In contrast, Nitrogen (N) is a group 5 element and needs to gain 3 electrons to achieve noble gas, hence it has a charge of (-3) charge. A neutral molecule has the sum of oxidation states of all atoms equal to zero. Hence 3 molecules of lithium and 1 molecule of nitrogen give a neutral molecule.

$Li_3N= 3\times(+1) + (-3) =0$

Therefore 3,1 is the correct answer, $Li_3N$

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2. Write the chemical equations for the neutralization reactions that occurred when HCL and NaOH were added to the buffer soluti

lutik1710 [3]

Answer:

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

Explanation:

A buffer is a solution that resists changes in acidity or alkalinity. A buffer is able to neutralize a little amount of acid or base thereby maintaining the pH of the system at a steady value.

A buffer may be an aqueous solution of a weak acid and its conjugate base or a weak base and its conjugate acid.

The equations for the neutralizations that occurred upon addition of HCl or NaOH are;

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

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A 20.00 ml sample of a solution of sr(oh)2 is titrated to the equivalence point with 40.03 ml of 0.1159 n hcl. what is the molar

goblinko [34]

The molarity of Sr(OH)2 solution is = 0.1159 M

calculation
write the equation for reaction
that is, Sr(OH)2 +2HCl→ SrCl2 + 2 H2O

then finds the mole of HCl used

moles = molarity x volume
=40.03 x0.1159 = 4.639 moles

by use of mole ratio between Sr(OH)2 to HCL which is 1 :2 the moles of Sr(OH)2 is therefore = 4.639 x1/2 = 2.312 moles

molarity of Sr(OH)2 is = moles / volume

=2.312 /20 =0.1159 M

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6.0*2 moles/ 1 mole

= 12 moles

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