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2 years ago

Work out the size of resistance.

Chemistry

1 answer:

dedylja [7]2 years ago

8 0

Answer:

Step 1: Identify the resistivity (ρ) , length (L), and radius (r) of the wire. Step 2: Calculate the cross-sectional area of the wire using the formula for the area of a circle: A=πr2 A = π r 2 . Step 3: Calculate the resistance (R) of the wire using the formula for resistance: R=ρLA R = ρ L A

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germanium -66 has a half-life of 2.5 hours. you have 35 grams of radioactive material. after 16 days, how much radioactive mater

Maru [420]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

How many half-lives are in 16 days?

Multiply 16 by 24 (to get the total hours) and divide that by 2.5.

That is 153.6 half-lives.

35(0.5)^(153.6) represents the equation for this.

Simplify this and get 8.88 x 10^(-45).

There will be 2.02 x 10^(-45)g of germanium-66 sample remaining after 16 days.

Hope this helps!

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3 years ago

Two substances, A and Z, are to be identified. Substance A can not be broken down by a chemical change. Substance Z can be broke

I am Lyosha [343]

The answer is 3). This is because elements are the simplest form of a substance, and cannot be broken down any further. Compounds on the other hand are much more complex than elements and can be broken down INTO elements. For example, Na, sodium, is an element and cannot be broken down further. H2O, water, is a compound and can be broken down into Hydrogen and Oxygen.

4 0

3 years ago

25.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 28.11 mL of a 0.1311

LuckyWell [14K]

Answer:

Concentration of the H₂SO₄ solution is 0.0737 M

Explanation:

Equation of the neutralization reaction between the acid, H₂SO₄, and the base, NaOH, is given below:

H₂SO₄ + 2NaOH -----> Na₂SO₄ + 2H₂O

From the above equation, one mole of acid requires 2 moles of base for complete neutralization which occurs at phenolphthalein endpoint.

mole ratio of acid to base, nA/nB = 1:2

Concentration of the base, Cb = 0.1311 M

Volume of base, Vb, = 28.11 mL

Concentration of acid, Ca = ?

Volume of acid, Va + 25.0 mL

Using the formula, CaVa/CbVb = nA/nB

making Ca subject of the formula, Ca = Cb*Vb*nA/Va*nB

substituting the values into the equation

Ca = (0.1311 * 28.11 * 1) / 25.0 * 2 = 0.0737 M

Therefore, concentration of the H₂SO₄ solution is 0.0737 M

5 0

4 years ago

Please help

Natasha_Volkova [10]

Answer:

reactant side

in endothermic reactions; the reaction will proceed in the forward reaction.

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3 years ago

A 10-kg object is pushed across a rough surface. It begins at rest and accelerates to a speed of 4 m/s in a distance of 5m. Whic

Lynna [10]

Answer:

C) The object accelerates across the surface.

Explanation:

4 0

4 years ago

Work out the size of resistance.​

Work out the size of resistance.