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alexandr402 [8]
3 years ago
14

What does it mean if the salt decomposes to yield a volatile material

Chemistry
1 answer:
marusya05 [52]3 years ago
5 0
Well, clearly the calculated value for the number of hydrating water molecules would increase above its true level, because the total weight loss would be greater than expected. This is of course undesirable, but may usually be avoided by careful application of the experimental procedures. The signs to look for include 

<span>(a) loss of water of hydration usually occurs at a considerably lower temperature than decomposition of the salt, because the water molecules are not strongly bonded in the hydrated complex. Dehydration typically occurs in a broad range of temperatures, typically from 50°C to around 200°C, whereas decomposition of the dehydrated salt generally takes place at temperatures over 200°C and in some case over 1000°C. So dehydration should be performed with care - avoid over-heating the sample in order to ensure that all the water has been driven off. </span>

<span>(b) dehydration often results in a change of appearance of the sample, particularly the colour and particle size of crystalline hydrates. However, decomposition may be accompanied by an additional change at higher temperatures, which gives a warning of its occurrence. </span>

<span>(c) if it is suspected that decomposition is occurring, or that dehydration is not complete, exploratory runs of varying duration at a given temperature may be carried out. There are two criteria to judge the effectiveness of the procedure </span>

<span>(i) the weight of the sample decreases to a constant stable value: this is a sign that dehydration is complete and decomposition - which is usually a much slower process - is not occurring. </span>

<span>(ii) the calculated number of molecules of water lost should take an integer value. If it differs by more than, say, 0.1 from an integer than it is probable that one of these two undesirable effects is present. Some hydrates lose water in steps through intermediate compounds with a lower level of hydration. These may provide plateaus where the weight loss is stable but dehydration is not complete. These will, in general, not provide an integer value for the number of water molecules present (because the calculation is based on the assumption that the residual sample is completely dehydrated salt).</span>
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A compound is found to contain 58.80 % xenon, 7.166 % oxygen, and 34.04 % fluorine by mass. what is the empirical formula for th
marissa [1.9K]
To make it easier, assume that we have a total of 100 g of a compound. Hence, we have 58.80g of xenon, 7.166g of oxygen, and 34.04g of fluorine. 
Know we will convert each of these masses to moles by using the atomic masses:

58.8/131.3 = 0.45 mole of Xe
7.166/16 = 0.45 mole of O
34.04/19 = 1.79 mole of F

Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the compound:

Xe = 0.45/0.45 = 1
O = 045/0.45 = 1
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3 years ago
A runner averages 8 minutes and 25 seconds per mile. What is her average velocity in miles per hour?
labwork [276]

8 minutes and 25 seconds is the same as 8.25 in decimal form.

Divide by 60 minutes.

60 / 8.25 = 7.27 miles per hour

Best of Luck!

6 0
3 years ago
Given the formula of a compound
Yuki888 [10]

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How many grams of aluminum sulfate: Al2(SO4)3 , would be formed if 250 g of H2SO4 react with aluminum? The reaction is: 2Al + 3H
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Answer:

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

Explanation:

Step 1: Data given

Mass of H2SO4 = 250 grams

Molar mass H2SO4 = 98.08 g/mol

Step 2: The balanced equation

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

Step 3: Calculate moles H2SO4

Moles H2SO4 = mass H2SO4 / molar mass H2SO4

Moles H2SO4 = 250 grams / 98.08 g/mol

Moles H2SO5 = 2.55 moles

Step 4: Calculate moles Al2(SO4)3

For 2 moles Al we need 3 moles H2SO4 to produce 1 mol Al2(SO4)3 and 3 moles H2

For 2.55 moles H2SO4 we'll have 2.55/3 = 0.85 moles Al2(SO4)3

Step 5: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass

Mass Al2(SO4)3 = 0.85 moles * 342.15 g/mol

Mass  Al2(SO4)3 = 290.8 grams

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

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4 years ago
When do d orbitals start getting filled
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Answer & Explanation:

D orbitals begin filling with electrons after the orbital found in the 4s sublevel is filled. This occurs because the d sublevel is first found in the.

8 0
3 years ago
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