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alexandr402 [8]
3 years ago
14

What does it mean if the salt decomposes to yield a volatile material

Chemistry
1 answer:
marusya05 [52]3 years ago
5 0
Well, clearly the calculated value for the number of hydrating water molecules would increase above its true level, because the total weight loss would be greater than expected. This is of course undesirable, but may usually be avoided by careful application of the experimental procedures. The signs to look for include 

<span>(a) loss of water of hydration usually occurs at a considerably lower temperature than decomposition of the salt, because the water molecules are not strongly bonded in the hydrated complex. Dehydration typically occurs in a broad range of temperatures, typically from 50°C to around 200°C, whereas decomposition of the dehydrated salt generally takes place at temperatures over 200°C and in some case over 1000°C. So dehydration should be performed with care - avoid over-heating the sample in order to ensure that all the water has been driven off. </span>

<span>(b) dehydration often results in a change of appearance of the sample, particularly the colour and particle size of crystalline hydrates. However, decomposition may be accompanied by an additional change at higher temperatures, which gives a warning of its occurrence. </span>

<span>(c) if it is suspected that decomposition is occurring, or that dehydration is not complete, exploratory runs of varying duration at a given temperature may be carried out. There are two criteria to judge the effectiveness of the procedure </span>

<span>(i) the weight of the sample decreases to a constant stable value: this is a sign that dehydration is complete and decomposition - which is usually a much slower process - is not occurring. </span>

<span>(ii) the calculated number of molecules of water lost should take an integer value. If it differs by more than, say, 0.1 from an integer than it is probable that one of these two undesirable effects is present. Some hydrates lose water in steps through intermediate compounds with a lower level of hydration. These may provide plateaus where the weight loss is stable but dehydration is not complete. These will, in general, not provide an integer value for the number of water molecules present (because the calculation is based on the assumption that the residual sample is completely dehydrated salt).</span>
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A reaction vessel for synthesizing ammonia by reacting nitrogen and hydrogen is charged with 5.79 kg of h2 and excess n2. a tota
PIT_PIT [208]

Answer:

82.08 %

Explanation:

  • <em>The percent yield of the reaction = [(actual yield)/(calculated yield)] x 100. </em>

Actual yield = 26.80 kg.

  • <em><u>To get the calculated yield: </u></em>
  • The balanced equation of reacting N2 with H2 to produce NH3 is:

N₂ + 3H₂ → 2NH₃

  • It is clear that 1.0 mole of N₂ reacts with 3.0 moles of H₂ to produce 2.0 moles of NH₃.
  • N₂ is present in excess and H₂ is the limiting reactant.
  • We need to convert the mass of H₂ added (5.79 kg) to moles using the relation:

n = mass /molar mass = (5790 g) / (2.01 g/mol) = 2880.6 mol.

  • We can get the no. of moles of NH₃ produced.

<u><em>Using cross multiplication: </em></u>

3.0 mole of H₂ produce → 2.0 moles off NH₃, from the stichiometry.

2880.6 mol of H₂ produces → ??? moles of NH₃.

  • The no. of moles of NH₃ produced = (2880.6 mol)(2.0 mol) / (3.0 mol) = 1920.4 mol.
  • We can know get the calculated yield of NH₃ = no. of moles x molar mass = (1920.4 mol) (17.00 g/mol) = 32646.76 g ≅ 32.65 kg.

∴ <em>The percent yield of the reaction = [(actual yield)/(calculated yield)] x 100 = </em>[(26.8 kg) / (32.65 kg)] x 100 <em>= 82.08 %.</em>

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Answer:

B.

Explanation:

it's B because 4 x 2 is 8 and we all know 8 x 8 is 64. So the answer is B.

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Answer: two or more different pure substances, which may be elements or compounds.


Explanation:


The term varieties of matter is kind of ambiguos since it is not defined.


The best approach to the question is to think of matter as it can be classified into to kinds: pure substaces and mixtures.


Elements and compounds are pure substances.


Elements are pure substances constituted by only one kind of atoms. An element cannot be divided into simpler substances either by physical or chemical media.


A compound is a chemical combination of two or more different elements. A compound can be divided into simpler substances by chemical reactions, but not by physical media. The properties of compounds are different of those of the elements of which they are constituted. The composition of a compoind (ratio among its elements) is fixed.


A mixture is the physical combination of two or more pure substances (either different elements or compounds) which can be mixed in any proportion. This is, its composition is variable. The substances that form the mixture can be separated by physical media.




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