Answer: molecular formula = C12H16O8
Explanation:
NB Mm CO2= 44g/mol
Mm H2O= 18g/mol
Moles of CO2 = 36.86/44=0.84mol
0.84mole of CO2 has 0.84 mol of C
Moles of H2O = 10.06/18= 0.56mol
1mol of H20 contains 1mol of O and 2 mol H,
Hence there are 0.56mol O and (0.56×2)mol H
Hence the compound contains
C= 0.84 mol H= 1.12mol O=0.56mol
Divide through by smallest number
C= 0.83/0.56= 1.5mol
H= 1.12/0.55= 2mol
O= 0.56/0.56= 1mol
Multiply all by 2 to have whole number of moles = 3:4:2
Hence empirical formula= C3H4O2
(C3H4O2)n = 288.38
[(12×3) + 4+(16×2)]n= 288.38
72n=288.38
n= 4
:. Molecular formula=(C3H4O2)4= C12H16O8
Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
During this process. A. Solid turns directly into a Gas.
Answer is C.
Converting temperatures to degrees K: 33 degrees C = 306 K and -55 = 218 degrees K.
By the ideal gas law:-
760 * 0.50 / 306 = P * 0.10 / 218
P = 760 * 0.50 * 218 / 306 * 0.10
= 2700 mm Hg answer
Answer:
The water will absorb 1004.16 Joule of heat
Explanation:
Step 1: Data given
Mass of the metal = 58.00 grams
Temperature of the metal = 100.00 °C
Mass of water = 60.00 grams
Temperature of water = 18.00 °C
Final temperature = 22.00 °C
Specific heat of water = 4.184 J/g°C
Step 2: Calculate the amount of heat absorbed by the water in joules
Q = mass *specific heat *ΔT
⇒ with Q = the heat absorbed by water
⇒ with mass of water = 60.00 grams
⇒ with specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C
Q = 60.00 * 4.184 J/g°C * 4.0 °C
Q = 1004.16 J
The water will absorb 1004.16 Joule of heat
