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4 years ago

Which scientist is credited with developing the first scientific atomic theory?

Chemistry

1 answer:

Kitty [74]4 years ago

7 0

John Dalton is the answer to your question.

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(b) in the direct hydration method, ethene reacts with steam. The equation for this reaction is C2H4 + H2O = C2H5OH

ladessa [460]

Answer:

20 degree and 4000000N

3 0

3 years ago

A compound found in the athletes urine had a percent composition of 80.8% carbon, 8.97% hydrogen and 10.3% oxygen. What is the E

mojhsa [17]

Answer:

C21H2802

Explanation:

C=12g/mol

H=1g/mol

O=16g/mol

Part (C) of compound-80.18%

(0.8018 x 312)/12=21

Part (H) of compound-8.97%

(0.897 x 312)/1=28

Part (O) of compund-10.3%

(0.103 x 312)/16 = 2

Therefore the emp. formula is C12H28O2

8 0

3 years ago

Covalent bonds are formed when valence electrons are

mamaluj [8]

It’s b. Shared between two atoms.

5 0

3 years ago

Read 2 more answers

Answer the following question.

aivan3 [116]

Answer:

B) The north and south Poles

Explanation:

when dealing with magnets they have a negative and Positive charge on their south and north poles. Negative attacks with positive and positive with negative so both poles on each magnet should react to each other

4 0

3 years ago

Consider the reaction for the combustion of benzene: 2 C6H6(g) 15 O2(g) ---> 12 CO2(g) 6 H2O(l) What mass of H2O is produced

irakobra [83]

Answer: Mass of water produced is 17.3 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For benzene:

Given mass of benzene = 25.0 g

Molar mass of benzene= 78 g/mol

Putting values in equation 1, we get:

$\text{Moles of benzene}=\frac{25.0g}{78g/mol}=0.32mol$

The chemical equation for the reaction follows:

$2C_6H_6(g)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)$

As, oxygen is an excess reagent. Thus benzene is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of benzene produces 6 moles of water

So, 0.32 moles of benzene will produce = $\frac{6}{2}\times 0.32=0.96moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water= 18 g/mol

Moles of water = 0.96moles

Putting values in equation 1, we get:

$0.96mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=17.3g$

Thus mass of water produced is 17.3 grams

3 0

3 years ago