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Whitepunk [10]
3 years ago
7

Find the slope (7,-2) and (6,-2)

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0
I hope this helps you

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K to the power of 2-2k-24
insens350 [35]

Answer:

I don’t understand what you are asking

Step-by-step explanation:

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2 years ago
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What is the equation of a line that is perpendicular to this line and goes through the
-Dominant- [34]

Answer:

x + 3y + 9 = 0

Step-by-step explanation:

y=3x + 2

Coefficient of x = 3

Gradient (m) of line y= 3x + 2 is 3

Since the line passing through point

(3,-4) is perpendicular to line y=3x + 2

hence gradient (m) of the line is -1/3;

And hence it equation is given as;

y - y1 = m(x - x1)

y - (-4) = -1/3(x - 3)

multiplying through by 3;

3 × y + 3 × 4 = 3 × -1/3(x - 3)

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3 years ago
Iii Write down the length and width of the block.
Svetlanka [38]
Answer:
Length: 30
Width: 25
Height: 5
7 0
2 years ago
HELP DUE SUPER SOON!!
kow [346]

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2022 students

Step-by-step explanation:

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2 years ago
Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe
vovangra [49]

Answer:

1.3\cdot 10^3\text{ J}

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

W=Fd, where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by F_g=mg, where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, F_g=75\cdot 9.8=735\text{ N}. Since she raises her body 4.0 meters, the work done must be W=Fd=735\cdot 4=2940\text{ J}.

Since power is equal to work over time and t = 2.3 seconds, we have:

\displaystyle P=\frac{W}{t}=\frac{2940}{2.3}=\boxed{1278\text{ J}}\approx \boxed{1.3\cdot 10^3\text{ J}} (to two significant figures)

7 0
1 year ago
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