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Brums [2.3K]
3 years ago
14

A 54-foot piece of siding is cut into three pieces so that the second piece is three times as long as the first piece and the th

ird piece is five times as long as the first piece. If X represents the length of the first piece, find the lengths of all three pieces
Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

The lenght of the first piece is 6 feet.

The lenght of the second piece is 18 feet.

The lenght of the third piece is 30 feet.

Step-by-step explanation:

Let be:

x the lenght of the first piece (in feet).

3x the lenght of the second piece (in feet).

5x the lenght of the third piece (in feet).

You know that the total lenght of the  piece of siding is 54 feet. This means that:

x+3x+5x=54

Having this expression, you can solve for "x":

9x=54\\\\x=\frac{54}{9}\\\\x=6

Therefore, the lenght of the first piece is 6 feet.

Then:

3x=3(6)=18 (The lenght of the second piece is 18 feet)

5x=5(6)=30 (The lenght of the third piece is 30 feet)

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Step by Step Solution

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Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

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Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

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A = L^{2}

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L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

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n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

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