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IRINA_888 [86]
3 years ago
6

Can someone help me with this one

Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

x(2x+1)(x-2)

Step-by-step explanation:

x(2x^2-3x-2)

x(2x^2-4x+x-2)

x[2x(x-2)+1(x-2)]

x(2x+1)(x-2)

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The length of a rectangle is six times its width. The area of the
Anni [7]

Answer:

length= 42

width = 7

Step-by-step explanation:

4 0
2 years ago
Mr and mrs. Dorsey and their three children are fling to Springfield. The cost of each ticket is $179. Estimate how much the tic
Soloha48 [4]
<span>First figure out how many people there are all together. So mrs and mr is 2 there three children so 2+3=5 so next round 179 to 200 and multiply 200x5. To do that you can use the mental math way witch would be to take the whole number out of 200 and make it 2. Then take the 5 in 200x5 and multiply 2x5. Then add the 2 zeros there were. And your estamated answer would be 1,000.
2+3=5
179=200
200x5
2x5=10
1,000
To figure out your real answer you will have to take 179 and multiply it by 5 so it will look like this:
 34
179
x
   5
895
Soto conculde the answer would be:

Estamated: $1,000

Exact: $895

Hope this helps!</span>
7 0
3 years ago
Over a three-day weekend, a rental car agency charges $65 to rent a car plus $0.30 for each mile traveled. If y represents the t
SOVA2 [1]
Y=0.30x+65

point-slope form
3 0
3 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
Pls help me do you know the answer let me know
FrozenT [24]

Answer:

Are you telling us to answer it all?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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