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MariettaO [177]
3 years ago
12

S= 2d Solved for d —— T

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
The answer to the question

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Desmond measured a city park and made a scale drawing. The scale he used was 1 centimeter: 9 meters. The actual width of the soc
kupik [55]

Answer:

6 cm

Step-by-step explanation:

1 cm : 9 meters -->  1cm/9m

? cm : 54 meters -->  ?cm/54m

\frac{1}{9}=\frac{?}{54}; 54*\frac{1}{9}=?;6=?

7 0
3 years ago
Which statement compares the numbers correctly?
jeyben [28]

Answer:

The first statement is correct

Step-by-step explanation:

0.654 < 0.674 is correct because 0 is the same, 6 is the same, but 7 is larger than 5.

4 0
2 years ago
Factor the expression completely
Kisachek [45]

Answer:

2 ( 2x+3) (2x-3)

Step-by-step explanation:

8x^2-18Factor out the greatest common factor of 2

2( 4x^2 -9)

2 ( (2x)^2 - 3^2)

What is inside the parentheses is the difference of squares

a^2 - b^2 = (a+b)(a-b)  

2 ( 2x+3) (2x-3)

6 0
2 years ago
Read 2 more answers
The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal with a mean of 16.12 OZ and a
elena-14-01-66 [18.8K]

Answer: 90.82%

Step-by-step explanation:

Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .

Mean : \mu=16.12\text{ OZ}

Standard deviation: \sigma=0.09\text{ OZ}

Let X be the random variable that represents the amount of soda in bottles.

Formula for z-score : z=\dfrac{x-\mu}{\sigma}

Z-score for 16 oz: z=\dfrac{16-16.12}{0.09}=-1.33

Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_

P(x>60)=P(z>-1.33)=1-P(x\leq-1.33)=1-0.0917591=0.9082409\approx0.9082\approx90.82\%

Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .

8 0
3 years ago
What is the area of the triangle?
Katen [24]

Answer:

24

Step-by-step explanation:

multiply base x height

4 0
2 years ago
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