PLease state ure question if the bee is on a wall.Whaat size is the bee?
Answer:
B
Step-by-step explanation:
Answer:
yuh
Step-by-step explanation:
<u>Part</u><u> </u><u>(</u><u>a</u><u>)</u>

<u>Part</u><u> </u><u>(</u><u>b</u><u>)</u>

Answer: 42.25 feet
Step-by-step explanation:
We know that after "t" seconds, its height "h" in feet is given by this function:

The maximum height is the y-coordinate of the vertex of the parabola. Then, we can use the following formula to find the corresponding value of "t" (which is the x-coordinate of the vertex):

In this case:

Substituting values, we get :

Substituting this value into the function to find the maximum height the ball will reach, we get:
