For the right triangles below find the value of the side lengths a and c round your answers to the nearest tenth

What is the solution to the system of equations below?

Andre45 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

$y=-6x-10$

$y=-3x-21$

solving the system of the equations

Arrange the equation variables for elimination

$\begin{bmatrix}y+6x=-10\\ y+3x=-21\end{bmatrix}$

$y+3x=-21$

$-$

$\underline{y+6x=-10}$

$-3x=-11$

$\begin{bmatrix}y+6x=-10\\ -3x=-11\end{bmatrix}$

solve

$-3x=-11$

Divide both sides by -3

$\frac{-3x}{-3}=\frac{-11}{-3}$

$x=\frac{11}{3}$

$\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=\frac{11}{3}$

$y+6\cdot \frac{11}{3}=-10$

$y=-32$

Therefore, the solutions to the system of the equations are:

$y=-32,\:x=\frac{11}{3}$

But, it seems none of the options is true.

8 0

3 years ago

Read 2 more answers

A publisher wants to figure out how thick there new book will be the book has a front cover and a back cover, each of which have

vfiekz [6]

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Using the properties of integer exponents, match each expression with its equivalent expression.

arrowRight

arrowRight

arrowRight

arrowRight

4 0

3 years ago

From a survey of 60 students attending a university, it was found that 9 were living off campus, 36 were undergraduates, and 3 w

lana66690 [7]

I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.

6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students

Therefore, there are 18 students who are neither an undergraduate nor living off-campus

8 0

3 years ago

Hope someone can help me

Advocard [28]

Hi!

Let's find out how much he has to pay for each of the deals.

Deal 1

£1.75 per mile.

192 x 1.75 = 336

£336

Deal 2

15% off of £680

$\frac{x}{680} \frac{15}{100}$

680 x 15 = 10200

10200/100 = 102

680 - 102 = 578

£578

Deal 3

£90 per day - 1/10

90 x 7 = 630

1/10 of 630 = 63

630 - 63 = 567

£567

The cheapest deal would be Deal 1

Hope this helps! :)

-Peredhel

5 0

3 years ago

209 is what percent of 475?

professor190 [17]

Answer:

44%

Step-by-step explanation:

1) You divide 209 by 475

2) Take 0.44 and move the decimal over 1 place to make <u>44%</u>

8 0

3 years ago