Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
Answer:
8 years approximately
The problem (I'm assuming is):
Solve 
.
I put a t in the problem where I suspected it in went.
Step-by-step explanation:
Divide both sides by 100:
Rewrite in logarithm form.
Divide both sides by 0.05:
Put left hand side into calculator:
So about 8 years if I wrote down the equation correctly.
Answer:
2/5 is less than 2/3
2/5 < 2/3
Step-by-step explanation:
2/5 x 3=6/15 is small
2/3x5=1<u>0/15 is big</u>
The answer is a. Because when word phrases say “a number”, they are referring to the variable. For instance, x is the variable so x is “a number”.
<span>This is an example of the substitution property of equality, meaning that if pq = 3, you may substitute 3 for pq in another related equation. So if pq+rs=5 is true, then 3+rs=5 is true as well.</span>
