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Paraphin [41]
3 years ago
5

What is the greatest common factor of 42a^5b^3, and 42ab^4

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0
The greatest common factor of 36x3 and 8x is simply 4X
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Someone please help
KIM [24]

Answer:

Step-by-step explanation:

Exponential function representing final amount with compound interest compounded continuously,

A=Pe^{rt}

Here, A = Final amount

P = principal amount

r = Rate of interest

t = Duration of investment

For P = $9600

r = 6%

A = 2 × 9600 = $19200

By substituting these values in the formula,

19200=9600(e)^{0.06\times t}

2=e^{0.06t}

ln(2)=ln(e^{0.06t})

ln(2) = 0.06t

t = \frac{0.693147}{0.06}

t = 11.55245

t ≈ 11.5525 years

Any amount will get doubled (with the same rate of interest and duration of investment) in the same time.

Therefore, $960000 will get doubled in 11.5525 years.

6 0
3 years ago
What is the value of x? Enter your answer in the box.
Pavlova-9 [17]
The answer to x would be 0

5 0
3 years ago
Timed help asap free 30 points after if correct find the value of the polynomial x^2-3xy+1/2 y^2 if x=3,y-2
BARSIC [14]

Answer:

Ans: 29

Step-by-step explanation:

soln:

Given,

x=3 and y=-2

Now,

x^2-3xy+1/2y^2

= 3^2-3×3×(-2) +1/2(-2)^2

= 9+18+4/2

= (18+36+4) /2

= 58/2

= 29 Ans

7 0
3 years ago
If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?
aksik [14]

ab = 8 & a^{2} + b^{2} = 16 so , ( a+b )^{2} = 32 .

<u>Step-by-step explanation:</u>

Here we have , ab= 8 & a^2+b^2=16 i.e. ab = 8  and a^{2} + b^{2} = 16 .

We need to find value of (a+b)^2 i.e. (a+b)^{2} :

It's and identity and we know that ( a+b )^{2} = a^{2} +b^{2} +2ab

⇒ ( a+b )^{2} = a^{2} +b^{2} +2ab

⇒ ( a+b )^{2} = (a^{2} +b^{2}) +2(ab)

⇒ ( a+b )^{2} = (16) +2(8)

⇒ ( a+b )^{2} = (16) +(16)

⇒ ( a+b )^{2} = 32

∴ ab = 8 & a^{2} + b^{2} = 16 so , ( a+b )^{2} = 32 .

6 0
3 years ago
A rectangle that is 2 inches by 3 inches has been scaled by a factor of 7. What are the side lengths of the scaled copy? Give th
Liono4ka [1.6K]

Answer:

Step-by-step explanation:

Nbv

7 0
3 years ago
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