1) f(x)=2x+6
f(2)=2(2)+6
=4+6
=10
2)f(x)=3x
f(a+1)=3(a+1)
=3a+3
3)f(x)=3x-1 and g(x)=5x+3
f(2)=3(2)-1
f(2)=6-1
=5
g(3)=5x+3
=5(3)+32
=15+3
=18
f(2)+f(3)=5+18
=23.
Answer:
Not a solution.
Step-by-step explanation:
(x, y)
(-1, 2)
Substitute the x and y values in the expression with the point given.
8x + y > -6
8(-1) + 2 > -6
-8 + 2 > -6
-6 > -6
Since our final value has to be greater than -6 but is instead equal to -6, the solution is not true.
Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
Answer:
c = $5,400
Step-by-step explanation:
Given:
c = 0.9s
where,
s = amount sold
c = commission on sales
How much commission will he or she earn if the amount sold is $6,000?
Find c when she = $6,000
c = 0.9s
= 0.9 × 6,000
= 5,400
c = $5,400
(c, s) (5400, 6000)
I think its (<span><span>x^2)</span>+<span>5x</span></span>+<span>49</span>
