Answer:
1) maximum electric field strength = 0.016 V/m
2)maximum magnetic field strength = 5.33 x 10^(-11) T
3) wavelength = 3 x 10^(8)m
Explanation:
A) We are given;
Frequency (f) = 1 Hz
Maximum Potential ΔV = 4 mV = 4 x 10^(-3) V
Length; d = 0.25 m
Now, maximum potential formula is given as;
ΔV = E_o•d
Where E_o is maximum electric field strength.
Thus,
E_o= ΔV/d = (4 x 10^(-3))/0.25 = 0.016 V/m
B) The maximum magnetic field strength is given by;
B_o = E_o/c
Where;
c is speed of light = 3 x 10^(8)
B_o is maximum magnetic field strength
Thus,
B_o = 0.016/(3 x 10^(8)) = 5.33 x 10^(-11) T
C) Speed of any electromagnetic wave is given by;
c = fλ
Where;
f is frequency
λ is wavelength
c is speed of light = 3 x 10^(8)
Thus, making λ the subject,
λ = c/f
λ = (3 x 10^(8))/1 = 3 x 10^(8)m
