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andrezito [222]
3 years ago
6

A caterpillar climbs up a one-meter wall. For every 2 cm it climbs up, it slides down 1 cm. It takes 10 minutes for the caterpil

lar to climb to the top. Calculate the time involved in seconds (not minutes).
Physics
2 answers:
Brut [27]3 years ago
6 0

100cm to go in 600 secs = 10mins

2 positive, 1 negative .... net 1 positive per step

ipn [44]3 years ago
3 0

Answer:

600 seconds.

Explanation:

A caterpillar climbs up a one meter (100 cm) wall.

For every 2 cm caterpillar climbs up and slides down 1 cm.

That means caterpillar climbs up = 2 - 1 = 1 cm

Caterpillar reaches to the top in 10 minutes. We have to calculate the time in seconds.

Since 1 minute = 60 seconds

Therefore, 10 minutes = 10×60 = 600 seconds

Time involved for the caterpillar to climb to the top will be 600 seconds.

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A charge Q is transferred from an initially uncharged plastic ball to an identical ball 10.0 cm away. The force of attraction is
victus00 [196]

Answer:

a charge Q is transferred from an initially uncharged

Explanation:

Hope this helps!

5 0
2 years ago
The world will face energy crisis in near future justify this statement
jeka57 [31]

Answer:

Nowadays most of our works are being done through different types of energy which are non-renewable. People are wasting lot of energy (hydel, dolar etc.) due to which in future we can face energy crisis.

5 0
2 years ago
An elevator and its load have a combined mass of 1650 kg. Find the tension in the supporting cable when the elevator, originally
gizmo_the_mogwai [7]

Answer:

Tension in the supporting cable is = 4,866 N ≅4.9 KN

Explanation:

First of all, we need to understand that tension is a force, so the motion law

F = Ma applies perfectly.

From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.

Parameters given:

Mass of load = 1650 kg

Acceleration of load = ?

The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.

Time taken = distance covered / velocity

= \frac{41m}{11m/s} = 3.73 seconds

∴Acceleration = ( initial velocity - final velocity )/ time taken

Note: Final velocity is = 0 since the body came to a rest.

Acceleration = \frac{11 - 0 m/s}{3.73s} = 2.95m/s^{2}

Force acting on the cable = mass of elevator × acceleration of elevator

= 1650 × 2.95 = 4869.5 kg ≅ 4.9 KN

6 0
2 years ago
Tarzan (75 kg) swings from 4 metres high on a vine down to ground level and catches Jane (50 kg). How fast are they moving after
Kruka [31]

Try this solution (if it is possible, check it in other sources):

1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:

E=m_{Tarzan}*(H_{initial}-H_{end})*g=75*4*10=3000(J).

2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:

E=\frac{m_{Tarzan+Jane}* Speed^2}{2}; \ => \ Speed=\sqrt{ \frac{2*E}{m_{Tarzan+Jane}}};

3. According to the formula of the Speed:

Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)


Answer: 6.84 (m. per sec.)

5 0
3 years ago
Momentum data about the same objects in the same closed system is shown below.
nalin [4]

Answer:

the value of x is 3.7 because they are arranged in a particular manner.

6 0
3 years ago
Read 2 more answers
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