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3 years ago

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The electric field 0.500 m from a charge is 3370 N/C, pointing away from the charge. What is the charge? Include the sign of the

charge, + or - (The answer is *10^-8 C. Just fill in the number, not the power.) (Unit = C)

1 answer:

iragen [17]3 years ago

3 0

Answer: 9.36 is correct on acellus

Explanation:

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A boy and a girl are on a spinning merry-go-round. The boy is at a radial distance of 1.2 m from the central axis; the girl is a

Licemer1 [7]

Answer:

E) True. The girl has a larger tangential acceleration than the boy.

Explanation:

In this exercise they do not ask us to say which statement is correct, for this we propose the solution to the problem.

Angular and linear quantities are related

v = w r

a = α r

the boy's radius is r₁ = 1.2m the girl's radius is r₂ = 1.8m

as the merry-go-round rotates at a constant angular velocity this is the same for both, but the tangential velocity is different

v₁ = w 1,2 (boy)

v₂ = w 1.8 (girl)

whereby

v₂> v₁

reviewing the claims we have

a₁ = α 1,2

a₂ = α 1.8

a₂> a₁

A) False. Tangential velocity is different from zero

B) False angular acceleration is the same for both

C) False. It is the opposite, according to the previous analysis

D) False. Angular acceleration is equal

E) True. You agree with the analysis above,

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3 years ago

Differentiate amihan and habagat

nasty-shy [4]

Answer:

Amihan is known as the Northeast monsoon while Habagat is known as the Southwest monsoon.

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2 years ago

A simple pendulum consists of a 2 kg bob attached to a 1.5 m long string. How much time (in s) is required for this pendulum to

Charra [1.4K]

Answer:

6.15 s

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

For the pendulum in this problem,

L = 1.5 m (length)

$g=9.8 m/s^2$ (acceleration due to gravity on Earth)

Therefore, its period is

$T=2\pi \sqrt{\frac{1.5}{9.8}}=2.46 s$

And therefore, the time taken for the pendulum to complete 2.5 oscillations is equal to 2.5 times the period:

$t=2.5T=(2.5)(2.46)=6.15 s$

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3 years ago

The sun radiates about 3.6 x 10^26 Joules of energy each second. How much mass does the sun lose each second?

natulia [17]

<span> In round figures, the solar converts 700 Million plenty of Hydrogen into 695 lots of </span>

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3 years ago

An object is attached to a vertical spring and bobs up and down between points A and B. Where is the object located when its kin

gtnhenbr [62]

Answer:

a. at either A or B

Explanation:

Kinetic energy may be defined as the energy of the system or an object which is due to its velocity of the object it possess.

In the context, an object having mass is attached to spring which is vertical and the object moves up and down due to spring effect between points A and B. Now these points A and B are the extreme points after which the object bounces back.

At point A and B, the velocity of the object becomes zero and hence the kinetic energy of a body varies directly proportional to its velocity.

i.e. Kinetic energy $= \frac{1}{2} \text{mass} \times (\text{ velocity})^2$

4 0

3 years ago