An car battery sends an electrical current one direction through a circuit in the car. Based on this, what type of current is a
1 answer:
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Answer: E = 7394.6N/C
Explanation:
Please find the attached file for the solution
Answer: F = 776.18N θ = 29.41°
Question:
The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.
Attached is the image.
Explanation:
To solve this question we need to resolve the forces to the x and y axis.
For the x axis;
Fcosθ = 700cos15....1
For the y axis;
200 = Fsinθ - 700sin15
Fsinθ = 200 + 700sin15 ...2
Dividing equation 2 by 1
Fsinθ/Fcosθ = (200 + 700sin15)/700cos15
Tanθ = (200 + 700sin15)/700cos15
θ = Taninverse(200 + 700sin15)/700cos15)
θ = 29.41°
From equation 1;
F = 700cos15/cosθ
F = 700cos15/cos29.41
F = 776.18N
Answer:
v= 3.18 m/s
Explanation:
Given that
m= 150 g = 0.15 kg
M= 240 g = 0.24 kg
Angular speed ,ω = 150 rpm
The speed in rad/s
ω = 15.7 rad/s
The distance of center of mass from 150 g
r= 20.30 cm
The speed of the mass 150 g
v= ω r
v= 20.30 x 15.7 cm/s
v= 318.71 cm/s
v= 3.18 m/s