Which of the following sets of characteristics describes the image formed by a plane mirror?A. Virtual and invertedB. Real and u
prightC. Virtual and uprightD. Real and invertedE. All the previous statements can be correct
1 answer:
<h2>Answer: Virtual and upright</h2><h2 />
A plane mirror is a highly polished flat surface with a very high capacity to reflect incident light.
We can understand in a better way how this works with the figure attached:
1. The incident rays coming from the real object reach the mirror and
2.are reflected following the law of Reflection.
3.The prolongation of those reflected rays converge at a point that does not coincide with the actual position of the object. At that point the virtual image of the object is formed.
4.Then, the reflected divergent rays are captured by our eye converging on the retina.
Now, the image is said to be virtual because it is a copy of the object that looks as if the object is behind the mirror and not in front of it or on the surface, but it is not really there. However, it can be seen when we focus it with our eyes.
In addition, the image formed is:
symmetrical, because apparently it is at the same distance from the mirror
the same size as the object.
upright, because it retains the same orientation as the object.
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Answer:
The Magnitude of electric field is in the upward direction as shown directly towards the charge .
Explanation:
Given:
- side of a square,
- charge on one corner of the square,
- charge on the remaining 3 corners of the square,
<u>Distance of the center from each corners</u>
∴Distance of center from corners,
Now, electric field due to charges is given as:
<u>For charge we have the field lines emerging out of the charge since it is positively charged:</u>
<u>Force by each of the charges at the remaining corners:</u>
<u> Now, net electric field in the vertical direction:</u>
<u>Now, net electric field in the horizontal direction:</u>
So the Magnitude of electric field is in the upward direction as shown directly towards the charge .
Answer:
The doppler effect equation is:
In the equation we have frequencies, but then we have the wavelengths of the lights, remember the relation:
v = f*λ
then:
f = v/λ
and v is the speed of light, then:
f = c/λ
where:
f' is the observed frequency, in this case, is equal to f = (3*10^17nm/s)/550 nm
f is the real frequency, in this case, is (3*10^17nm/s)/650 nm
vs is the speed of the source, in this case, the source is not moving, then vs = 0 m/s.
v is the speed of the wave, in this case, is equal to the speed of light, v = 3*10^8 m/s
v0 is your speed, this is what we want to find.
Replacing those quantities in the equation, we get:
(3*10^17nm/s)/550 = (3*10^8 m/s + v0)/(3*10^8 m/s)*(3*10^17nm/s)/650 nm
(650nm)/(550nm) = (3*10^8 m/s + v0)/(3*10^8 m/s)
1.182*(3*10^8 m/s) = (3*10^8 m/s + v0)
1.182*(3*10^8 m/s) - (3*10^8 m/s) = v0 = 54,600,000 m/s
So your speed was 54,600,000 m/s, which is a lot.