1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dsp73
3 years ago
8

Among 9 electrical components exactly one is known not to function properly. if 4 components are randomly selected, find the pro

bability that at least one does not function properly.
Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0

Answer:

The probability is 0.44444.

Step-by-step explanation:

Among 9 electrical components exactly one is known not to function properly.

This means 8 components work properly.

If 4 components are randomly selected, the probability that at least one does not function properly is :

\frac{8c3 \times1c1}{9c4}

= \frac{56}{126} =0.44444

Answer: The probability is 0.44444.

seraphim [82]3 years ago
4 0

Answer:

0.4444

Step-by-step explanation:

Use the following property to ease the calculation:

P(At least one)=1-P(None)

Total number of electrical components: 9

Number that does not function well :1

Number that functions well : 8

We have ^8C_4=70 ways to to choose 4 good components from 8.

We have ^9C_4=126 ways to choose 4 components from a total of 9.

If all function properly then none is bad, we ^1C_0=1 way to do this.

P(At least one)=1-\frac{^8C_4*^1C_0}{^9C_4}

P(At least one)=1-\frac{70*1}{126}

P(At least one)=0.4444

You might be interested in
7x <br> 5x+18 <br> Find the size of the smallest angle
allochka39001 [22]

Answer

Not sure is there supposed to be a pic?

Step-by-step explanation:

3 0
2 years ago
Please help me answer question B!
skelet666 [1.2K]

Answer:

  • The program counter holds the memory address of the next instruction to be fetched from memory
  • The memory address register holds the address of memory from which data or instructions are to be fetched
  • The memory data register holds a copy of the memory contents transferred to or from the memory at the address in the memory address register
  • The accumulator holds the result of any logic or arithmetic operation

Step-by-step explanation:

The specific contents of any of these registers at any point in time <em>depends on the architecture of the computer</em>. If we make the assumption that the only interface registers connected to memory are the memory address register (MAR) and the memory data register (MDR), then <em>all memory transfers of any kind</em> will use both of these registers.

For execution of the instructions at addresses 01 through 03, the sequence of operations may go like this.

1. (Somehow) The program counter (PC) is set to 01.

2. The contents of the PC are copied to the MAR.

3. A Memory Read operation is performed, and the contents of memory at address 01 are copied to the MDR. (Contents are the LDA #11 instruction.)

4. The MDR contents are decoded (possibly after being transferred to an instruction register), and the value 11 is placed in the Accumulator.

5. The PC is incremented to 02.

6. The contents of the PC are copied to the MAR.

7. A Memory Read operation is performed, and the contents of memory at address 02 are copied to the MDR. (Contents are the SUB 05 instruction.)

8. The MDR contents are decoded and the value 05 is placed in the MAR.

9. A Memory Read operation is performed and the contents of memory at address 05 are copied to the MDR. (Contents are the value 3.)

10. The Accumulator contents are replaced by the difference of the previous contents (11) and the value in the MDR (3). The accumulator now holds the value 11 -3 = 8.

11. The PC is incremented to 03.

12. The contents of the PC are copied to the MAR.

13. A Memory Read operation is performed, and the contents of memory at address 03 are copied to the MDR. (Contents are the STO 06 instruction.)

14. The MDR contents are decoded and the value 06 is placed in the MAR.

15. The Accumulator value is placed in the MDR, and a Memory Write operation is performed. Memory address 06 now holds the value 8.

16. The PC is incremented to 04.

17. Instruction fetch and decoding continues. This program will go "off into the weeds", since there is no Halt instruction. Results are unpredictable.

_____

Note that decoding an instruction may result in several different data transfers and/or memory and/or arithmetic operations. All of this is usually completed before the next instruction is fetched.

In modern computers, memory contents may be fetched on the speculation that they will be used. Adjustments need to be made if the program makes a jump or if executing an instruction alters the data that was prefetched.

4 0
3 years ago
Help me please and thank u
marin [14]

\large \mathfrak{Solution : }

As we know :

Dividend = Divisor × Quotient ( taking remainder as 0 )

So, Quotient = Dividend ÷ Divisor

by using the above relation we can say :

  • q = t ÷ 23

therefore, correct option is C. t ÷ 23

6 0
3 years ago
Use a model to divide. 1/2÷7 . What is the answer 2/7 1/14 14 3 1/2?
shutvik [7]

Answer:

1/14 i think

Step-by-step explanation:

7 0
3 years ago
Please Help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Oduvanchick [21]

Answer:

26:26

Step-by-step explanation:

I hope I've helped :)

4 0
2 years ago
Other questions:
  • What is 37 divided by 748​
    10·1 answer
  • Number of the day 3.59
    7·1 answer
  • 10(-2 - 9v) what is it
    13·1 answer
  • Which number rounds to 20,000 to the nearest hundred and thousand?
    6·1 answer
  • Circle O has a circumference of approximately 44 in.
    10·1 answer
  • okay so for some reason my mind went completely blank and forgot how to do pathagoream theorem. so like could you tell me the st
    8·2 answers
  • What are the domain and range of f(x) = 2|x -4|? <br> plz i'm in need
    9·1 answer
  • Can someone help me figure this out?​
    7·2 answers
  • Amelia went to the candy store and bought 5/6 of a pound of candy. If 1/2 of Amelia's candy
    6·2 answers
  • The area of the rectangle on the bottom of this stack is 6 cm2 and the height of the stack is 3 cm. What is the volume of this r
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!