What is the thick outer layer of a plant cell

Can mRNA coding for a protein destined to be embedded in the plasma membrane associate with rough ER prior to the initiation of

Debora [2.8K]

Answer:

mRNA must start membrane protein in the cytoplasm and, after that, continue it in the rough ER.

Explanation:

Protein synthesis is initiated when mRNA meets a free ribosome, the primary structure for protein synthesis. Ribosomes can be found in the rough endoplasmic reticulum or floating in the cytosol. They read the mRNA code and add the correct amino acid using transference RNA to build the protein.

The rough endoplasmic reticulum is in charge of the synthesis and transport of the membrane proteins. It is also in charge of the latest protein modifications after transduction. Synthesis of membrane proteins starts in the cytoplasm with the production of a molecule portion known as a signal sequence. This portion leads the synthesizing protein and associated ribosome to a specific region in the Rough endoplasmic reticulum where it continues the protein building.

Membrane proteins are synthesized in the endoplasmic reticulum and sent to the Golgi complex in vesicles, where it happens the final association of carbohydrates with proteins. Finally, protein is transported from the Golgi complex to its final destiny, the membrane.

4 0

3 years ago

Match each interaction with its description.

Natalka [10]

There is competition among species when they jostle for scarce resources.

<h3>What is competition?</h3>

The term competition has to do with a situation in which members of the same species scramble for scarce resources.

The following are the definitions of the types of competition;

interference competition - An individual directly interacts and changes the way other individuals attain resources.

apparent competition - Individuals do not compete directly for resources, but are prey for the same predator.

exploitation competition - Individuals interact indirectly while competing for common resources.

Learn more about competition among organisms:brainly.com/question/13775651

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6 0

2 years ago

Why is it that scientists have trouble when it comes to RNA viruses?

olchik [2.2K]

RNA viruses can copy themselves which is harder for scientists to give an accurate conclusion to solve them.

8 0

3 years ago

La Rafflesia arnoldii es una planta tropical con una enorme flor rojo-sangre, que emite calor y despide olor a carne descompuest

Bingel [31]

Answer:

Rafflesia arnoldii is a tropical plant with a huge blood-red flower, which emits heat and emits the smell of decomposed meat. What use are these adaptations to this plant

Explanation:

The smell is adaptation for pollination.This is because it attracts insects which carry on the process of pollination.

Its possible Endothermy characteristic is for mimicry Its releases heat to attract the pollinators- blowflies.The endothermic mechanism is well pronounced during flora development: which further buttress the fact that this is related to pollination to attract blowflies, and not to thermoregulation.

8 0

3 years ago

In cats, curled ears result from an allele, Cu, that is dominant over an allele cu, for normal ears. Black color results from an

just olya [345]

Answer:

Explanation:

Cross : ggCuCu X GGcucu --------Parents

F1 progeny : GgCucu

Two of the F1 cats mate :

Cross : GgCucu X GgCucu

Gametes :

Gg X Gg = GG, Gg, Gg, gg

Cucu X Cucu = CuCu, Cucu, Cucu, cucu

1/4 GG X 1/4 CuCu = 1/16 GGCuCu (black - curled ears)

1/4 GG X 2/4 Cucu = 2/16 GGCucu (black - curled ears)

1/4 GG X 1/4 cucu = 1/16 GGcucu (black - normal ears)

2/4 Gg X 1/4 CuCu = 2/16 GgCuCu (black - curled ears)

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 1/4 cucu = 2/16 Ggcucu (black - normal ears)

1/4 gg X 1/4 CuCu = 1/16 ggCuCu (gray - curled ears)

1/4 gg X 2/4 Cucu = 2/16 ggCucu (gray - curled ears)

1/4 gg X 1/4 cucu = 1/16 ggcucu (gray - normal ears)

Answer : (i). 9/16 black cats, curled ears; 3/16 black cats, normal ears; 3/16 gray cats, curled ears; and 1/16 gray cats, normal ears.

An F1 cat mates with a stray cat that is gray and possesses normal ears :

Cross : GgCucu X ggcucu

Gametes :

Gg X gg = Gg, Gg, gg, gg

Cucu X cucu = Cucu, Cucu, cucu, cucu

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 2/4 cucu = 4/16 Ggcucu (black - normal ears)

2/4 gg X 2/4 Cucu = 4/16 ggCucu (gray - curled ears)

2/4 gg X 2/4 cucu = 4/16 ggcucu (gray - normal ears)

Answer : (i). 1/4 black cats, curled ears; 1/4 black cats, normal ears; 1/4 gray cats, curled ears; 1/4 gray cats, normal ears.

6 0

3 years ago