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3 years ago

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Which inequality statement describes the two numbers on a number line? "−5 and a number 4 units to the right of −5" A) 4 < −5

B) 4 > −5 C) −5 > −1 D) −5 < −1
Edit: Just found out. Answer is D.

1 answer:

Marina CMI [18]3 years ago

8 0

Answer: D

Step-by-step explanation:be cause you have to add 4 to negetive 5 and and that negetive 1 which is greater than -5

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A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years

juin [17]

Answer: 0.55567

Step-by-step explanation:

Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.

i.e.

$\mu=10\text{ years}\\\sigma=3\text{ years}$

Let $X_1$ and $X_2$ are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator $X_3$ .

So that, $X =X_1+X_2-1.9\times X_3$

Mean $=E(X_1)+E(X_2)-E(X_3)=10+10-1.9\times10 =1$

Standard deviation = $\sqrt{(Var(X_1)+Var(X_1)+Var(X_1))}$

$=\sqrt{(3^2+3^2+(1.9\times3)^2)}$

$=7.1056315694$

Z-score : $z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14$

Now , The probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-

$P(Z>-0.14)=P(Z$

Hence, the required probability is 0.55567.

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3 years ago

The diameter of a circle is 8 inches. What is the area?

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3 years ago

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The difference between the roots of the equation 3x2+bx+10=0 is equal to 4 1 3 . find<br> b.

inna [77]

Given that the difference between the roots of the equation $3x^2+bx+10=0$ is $4 \frac{1}{3} = \frac{13}{3}$ .

Recall that the sum of roots of a quadratic equation is given by $- \frac{b}{a}$ .

Let the two roots of the equation be $\alpha$ and $\alpha + \frac{13}{3}$ , then

$\alpha + \alpha + \frac{13}{3} =2 \alpha + \frac{13}{3} =- \frac{b}{a} =- \frac{b}{3} \\ \\ i.e.\ \ 2 \alpha + \frac{13}{3}=- \frac{b}{3}$ . . . (1)

Also recall that the product of the two roots of a quadratic equation is given by $\frac{c}{a}$ , thus:

$\alpha \left( \alpha + \frac{13}{3} \right)= \alpha ^2+ \frac{13}{3} \alpha = \frac{c}{a} = \frac{10}{3} \\ \\ i.e.\ \ \alpha ^2+ \frac{13}{3} \alpha=\frac{10}{3}$ . . . (2)

From (1), we have:

$2 \alpha =- \frac{b}{3} - \frac{13}{3} \\ \\ \Rightarrow \alpha =- \frac{b}{6} - \frac{13}{6}$

Substituting for alpha into (2), gives:

$\left(- \frac{b}{6} - \frac{13}{6}\right)^2+ \frac{13}{3} \left(- \frac{b}{6} - \frac{13}{6}\right)= \frac{10}{3} \\ \\ \Rightarrow \frac{b^2}{36} + \frac{13b}{18} + \frac{169}{36} - \frac{13b}{18} - \frac{169}{18} = \frac{10}{3} \\ \\ \Rightarrow \frac{b^2}{36} - \frac{289}{36} =0 \\ \\ \Rightarrow \frac{b^2}{36} = \frac{289}{36} \\ \\ \Rightarrow b^2=289 \\ \\ \Rightarrow b=\pm\sqrt{289}=\pm17$

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B I think sorry if I’m wrong on mine it say that’s right

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Mrs. Rodrigues was selling two kinds of raffle tickets for $1.50 and $3.50. The number of $1.50 tickets sold was 5 more than thr

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