x=1 f = 10(5.5)(1) = 55
x=2, f = 10(5.5)(2) = 110
110-55 = 55
2-1 =1
55/1 = 55
average rate of change = 55
<h2>Question :</h2>
<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>
<h2>Answer :</h2>
<em>y = -3/2x - 4 </em>
<h2>Explanation :</h2>
y = mx + c
*m = gradien
•>looking for gradients
y=2/3x+9
m1 = 2/3
m2 = -3/2
•>line equation (-6,5)
y - y1 = m(x - x1)
y - 5 = -3/2(x - (-6))
y - 5 = -3/2(x + 6)
y - 5 = -3/2 - 9
y = -3/2x - 9 + 5
y = -3/2x - 4
AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
Answer:
7/20
Step-by-step explanation:
given,
2r = 7/10
r= 7/10*1/2
r= 7/20
