This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Answer:
undefined
Step-by-step explanation:
The line on the graph is completely vertical, which is characteristic of an undefined graph.
Answer:
B
Step-by-step explanation:
The figure is a trapezium with area (A) calculated as
A = 
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 8, a = 10 and b = 6, thus
A = × 8 × (10 + 6) = 4 × 16 = 64 cm² → B
The hundredths place is the number two to the right of the decimal(so the one in 0.01). The value would be 4.
Answer:
x = −1/13 and y = 33/13 or 2 7/13
Step-by-step explanation:
x+2y=5
x+2(6x+3)=5
x+12x+6=5
13x+6=5
-6 -6
13x= -1
/13 /13
<u>x= -1/13</u>
y=6x+3
y=6(-1/13)+3
y= 33/13
y= 2 7/13
