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2 years ago

6

Tell how to multiply two fractions give an example

1 answer:

mario62 [17]2 years ago

7 0

Ex 1:
2/5 x 4/5
Multiply both the numerators together and then multiply both the denominators together. You would multiply 2x4 which is 8 and 5x5 which is 25. Which leaves you with 8/25 and it will stay that way because you cannot simplify it further.

Ex 2:
2/5 and 5/3
Multiply across 2x5/5x3 and you end up with 10/15 which can be simplified/reduced to 2/3 because they share a common factor of 5.

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Which best describes a number that cannot be irrational

vazorg [7]

Am irrational number is a number that cannot be expressed as a fraction for any integers. numbers of the form,where is the logarithm, are irrational if and are integers, one of which has a prime factor which the other lacks. is irrational for rational

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3 years ago

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Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 3 at x = −3 and a local minimum value of 0 at

Amiraneli [1.4K]

Answer:

The cubic function is f(x) = (27/32)·x - 3/32·x³ - -9/32·x² - 9/32

Step-by-step explanation:

The given function is f(x) = a·x³ + b·x² + c·x + d

By differentiation, we have;

3·a·x² + 2·b·x + c = 0

3·a·(-3)² + 2·b·(-3) + c = 0

3·a·9 - 6·b + c = 0

27·a - 6·b + c = 0

3·a·(1)² + 2·b·(1) + c = 0

3·a + 2·b + c = 0

a·(-3)³ + b·(-3)² + c·(-3) + d = -3

-27·a + 9·b - 3·c + d = -3...(1)

a + b + c + d = 0...(2)

Subtracting equation (1) from equation (2) gives;

28·a - 8·b + 4·c = 3

Therefore, we have;

27·a - 6·b + c = 0

3·a + 2·b + c = 0

28·a - 8·b + 4·c = 0

Solving the system of equations using an Wolfram Alpha gives;

a = -3/32, b = -9/32, c = 27/32 from which we have;

a + b + c + d = 0 3 × (-3/32) + 2 × (-9/32) + (27/32) + d = 0

d = 0 - (0 3 × (-3/32) + 2 × (-9/32) + (27/32)) = -9/32

The cubic function is therefore f(x) = (-3/32)·x³ + (-9/32)·x² + (27/32)·x + (-9/32).

4 0

2 years ago

Help me with this question below

lutik1710 [3]

See attached picture for steps and answer:

3 0

2 years ago

I run a 10km race in 56 minutes.what is my average speed in kilometres per minute

Luden [163]

Hey there! I'm happy to help!

You ran a 10 kilometer race in 56 minutes (good job!). To find how much you ran in 1 minute, you simply divide by 56.

10/56=0.178571428

Therefore, you ran around 0.18 km/minute.

Have a wonderful day! :D

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3 years ago

Vera is using her phone.Its battery life is down to 2/5,and it drains another 1/9 every other. How many hours will her battery l

Margarita [4]

Let x be total hours of battery life. We have been given that battery life of Vera's phone is down to 2/5. So remaining battery life,

$1-\frac{2}{5}=\frac{5-2}{5}=\frac{3}{5}$

We have been also given that it drains another 1/9 every other hour. Now let us substitute our given information into an equation.

$\frac{1}{9}\cdot x=\frac{3}{5}$

Now we will solve for x.

$x=\frac{3\cdot 9}{5}=\frac{27}{5}$

$x=(5+\frac{2}{5})hours$

Let us convert 2/5 into minutes. We know 1 hour has 60 minutes.

$60\cdot \frac{2}{5}=24\text{minutes}$

Therefore, remaining battery life will be 5 hours and 24 minutes.

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3 years ago

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