21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
0.5 degrees is the answer you divided the quotion by 5 then get your answer (this isnt actually the answer lol)
Step-by-step explanation:
$6.48- $6.00= $.48
.48÷ 6.0= 0.08
0.08 = 8%
tax rate is 8%
charlie and sons- 75 x 100=7500 + 1000= $8500
home dreams- 80 x 100=8000 + 800= $8800
Dream house is more expensive
Brainliest Please!
Answer:
9/16
Step-by-step explanation:
3/16 + 2/16 + 4/16 = 9/16
