Question not well presented
Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS
Answer:
The numerical length of RS is 22
Step-by-step explanation:
Given that
RS = 4x − 10
ST=2x−10
RT=4x−4
From the question above:
Point S lies on |RT|
So, RT = RS + ST
Substitute values for each in the above equation to solve for x
4x - 4 = 4x - 10 + 2x - 10 --- collect like terms
4x - 4 = 4x + 2x - 10 - 10
4x - 4 = 6x - 20--- collect like terms
6x - 4x = 20 - 4
2x = 16 --- divide through by 2
2x/2 = 16/2
x = 8
Since, RS = 4x − 10
RS = 4*8 - 10
RS = 32 - 10
RS = 22
Hence, the numerical length of RS is calculated as 22
Answer:
25x² − 20x + 4
Explanation:
(5x − 2)²
= (5x + −2)(5x + −2)
= (5x)(5x) + (5x)(−2) + (−2)(5x) + (−2)(−2)
= 25x² − 10x − 10x + 4
= 25x² − 20x + 4
Answer:
Hello your answer should be: Bella saved more per chore than Sweet T.
Step-by-step explanation:
Hope this helped! :)
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