Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
Answer:
4/5 x 7/12 = 28/60 as simplified as 7/15 in fraction form. 4/5 x 7/12 = 0.4667 in decimal form.
[ Answer ]

[ Explanation ]
- Formula For Area Of Trapezoid:

-----------------------------------------
A = 10
B = 18
H = 6
- Plug Numbers Into Equation:

10 + 18 = 28
28 ÷ 2 = 14
14 · 6 = 84
84
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Answer:
D. y = |x| – 5.5
Step-by-step explanation: