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NemiM [27]
3 years ago
13

Define transfer function and find the transfer function of a closed loop control system?

Engineering
1 answer:
Vsevolod [243]3 years ago
8 0

Answer and explanation :

TRANSFER FUNCTION :  transfer function is defined as the ratio of output and input at zero initial condition it is commonly denoted by T(S)

TRANSFER FUNCTION OF A CLOSED LOOP :

for a closed loop transfer function

T=\frac{G}{1+GH}

where G is the forward path gain and H is the feedback gain close loop is formed when output is connect to input through a feedback this feedback may be a positive feedback or negative feedback but generally use negative feedback

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Which of the following actions by farmers contributes to desertification?
madreJ [45]

The answer to the question should be abandoning overused farmland without replenishment. when you dont use the land, it turns very dry

4 0
3 years ago
Determine the slopes and deflections at points B and C for the beam shown below by the moment-area method. E=constant=70Gpa I=50
inn [45]

Answer:

hello your question is incomplete attached below is the complete question

answer :

Slopes : B = 180 mm , C = 373 mm

Deflection: B = 0.0514 rad ,  C = 0.077 rad

Explanation:

Given data :

I = 500(10^6) mm^4

E = 70 GPa

The M / EI  diagram is attached below

<u><em>Deflection angle at B</em></u>

∅B = ∅BA = [ 150 (6) + 1/2 (300)*6 ] / EI

                 = 1800 / ( 500 * 70 ) = 0.0514 rad

<u><em>slope at B </em></u>

ΔB = ΔBA = [ 150(6)*3 + 1/2 (300)*6*4 ] / EI

                 = 6300 / ( 500 * 70 ) = 0.18 m = 180 mm

<u><em>Deflection angle at C </em></u>

∅C = ∅CA = [ 1800 + 300*3 ] / EI

                 = 2700 / ( 500 * 70 )

                 = 2700 / 35000 = 0.077 rad

<u><em>Slope at C </em></u>

ΔC = [ 150 * 6 * 6 + 1/2 (800)*6*7 + 300(3) *1.5 ]

     = 13050 / 35000 = 373 mm

3 0
3 years ago
A 65% efficient turbine receives 2 m^3/s of water from a reservoir. The reservoir water surface is 45 m above the centerline of
laiz [17]

Answer:

P_{out} = 508.071 kW

Given:

efficiency of the turbine, \eta = 65% = 0.65

available gross head,  H_{G} = 45 m

head loss,  H_{loss} = 5 m

Discharge, Q =  2 m^{3}

Solution:

The nozzle is 100% (say)

Available power at the inlet of the turbine,  P_{inlet} is given by:

P_{inlet} = \rho Qg(H_{G} - H_{loss})                  (1)

where

\rho = density of water = 997 kg/m^{3}

acceleration due to gravity, g = 9.8 m^{2}

Using eqn (1):

P_{inlet} = 997\times 2\times 9.8(45 - 5) = 781.65 kW

Also, efficency, \eta is given by:

\eta = \frac{P_{out}}{P_{inlet}}

0.65 = \frac{P_{out}}{781.648\times 1000}

P_{out} = 0.65\times 781.648\times 1000 = 508071 W = 508.071 kW

P_{out} = 508.071 kW

3 0
3 years ago
When handling chemicals and solvents, technicians are recommended to
Luda [366]

Answer:

  1. To wear PPE
  2. Have prior knowledge of explosive levels and elemental properties
  3. Know procedure to eliminate any threat
7 0
3 years ago
Read 2 more answers
If E = 94.2 mJ of energy is transferred when Q = 1.66 C of charge flows through a circuit element, what is the voltage across th
Anni [7]

Answer:

V = 56.8 mV

Explanation:

When a current I flows across a circuit element, if we assume that the dimensions of the circuit are much less than the wavelength of the power source creating this current, there exists a fixed relationship between the power dissipated in the circuit element, the current I and the voltage V across it, as follows:

P = V*I

By definition, power is the rate of change of energy, and current, the rate of change of the charge Q, so we can replace P and I, as follows:

E/t = V*q/t ⇒ E = V*Q

Solving for V:

V = E/Q = 94.2 mJ /1.66 C = 56.8 mV

6 0
3 years ago
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