Answer:
(a) T₂ =747.5 and K= 474.5 °C (b) 330.178 kJ/kg
Explanation:
Solution
T₁ = 35°C = 308
the first step to take is to Use the Table A-17: Ideal gas properties for air:
Now,
At T₁ = 308 K
V₁ = 217.67 + [308-305/310-305] (221.25 -217.67)
So,
V₁ =219.818 kJ/kg
Thus,
Vr₁ = 596 + [308-305/310-305] (572.3 - 596)
= 581.78
so,
Vr₂/Vr₁ = 1/10
Vr₂ =58.178
Applying Table A-17, at Vr₂ = 58.178
Then,
(a) T₂ = 740 + [58.178 - 59.82/57.63 -59.82] (750 -740)
T₂ = 747.5 and K = 474.5 °C
V₂ =544.02 + [58.178 - 59.82/57.63 -59.82] (551.99 - 544.02)
so,
V₂ =549.996 kJ/kg
Hence,
(b) q - w = v₂ -v₁
= 0 -w = 549.996- 219.818
w = 330.178 kJ/kg
Explanation:
are bhai brainly aap english me questions kar ne ko hai
ye kon si bhasha hai ??????
Answer:
n R ln(Vf/Vi)
Explanation:
Entropy is the loss of energy available to do work. Entropy is a state function (i.e. it depends only upon the current state of the system and is independent of how that state was prepared).
Since the temperature change of the ideal is constant, hence this is an isothermal expansion of a perfect gas. The change in entropy (ΔS) for an isothermal expansion of a perfect gas is given by:
Where n is the amount of gas molecules in mol and R is the gas constant in JK⁻¹mol⁻¹given by R = 
k, k is Boltzmann's constant in J K⁻¹ and Avogadro's constant in mol⁻¹. Vf is the final volume and Vi the initial volume.
Explanation:
To students of electronics, Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists. When spelled out, it means voltage = current x resistance, or volts = amps x ohms, or V = A x Ω.
Answer:
It is important for the client and the engineering team to maintain open communications even after the deliver of the product because
1) One of doctrine of Six Sigma which is a tool used to improve processes requires the input of effort meant to attain a stable process that can be easily predicted and geared towards the reduction of variation in the process is a pre requisite for the business to succeed
2) Communication can also help in product monitoring and control as well as ensuring that the product performance requirements are met
3) Communication between the client and the engineering team can serve as a means of reporting failures and collecting data for analysis
Explanation:
