Hello :
v . w = <span>| | v | | × </span><span>| | w | | cos(</span><span>θ) ....(1)
v(2,0,1) w(0,1,-3)
</span>v . w = (2)(0)+(0)(1)+(1)(-3) = - 3
| | v | | = √((2)²+(0)²+(1)²) = <span>√5
</span>| | w | = √((0)²+(1)²+(-3)²) = √10
by (1) :
cos(θ) = (v . w ) / | | v | | × | | w | |
cos(θ) = = - 3/√50
θ =..... calculate by 2ind function ( calculator)
The attached shows the two plots. The break-even points are near
x = 21
x = 256
Answer:
It should be <u>-5, 5 to the power of -1, 0.5, 5 to the power of 0</u> in least to greatest form.
Step-by-step explanation:
Answer:
theater
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