Answer:
132 mm^2
Step-by-step explanation:
The line added to the figure in the attachment shows it can be divided into two figures whose area is easily calculated.
1. A parallelogram of base length 20 mm and height 4 mm:
A = bh = (20 mm)(4 mm) = 80 mm^2
2. A trapezoid with bases 32 mm and 20 mm, and height 2 mm:
A = (1/2)(b1 +b2)h = (1/2)(32 mm +20 mm)(2 mm) = 52 mm^2
The total area of the figure is then ...
80 mm^2 +52 mm^2 = 132 mm^2
Answer: D
Step-by-step explanation:
A) 3*0^2+2(0-5)>8
-10>8 -> not true
B) 3*(-1)^2+2(-1-5)>8
3*1+2*(-6)>8
3- 12>8
-9> 8 -> not true
C) 3*(-2)^2+2(-2-5)>8
3*4+2*(-7)>8
12-14>8
-2> 8 -> not true
D) ) 3*(-3)^2+2(-3-5)>8
3*9+2*(-8)>8
27-16>8
11> 8 -> true
Answer:
(X - 3)*2
(X + 7)*5
(10 * X) + 20
Step-by-step explanation:
I used X as a replacement for "A number"
Hope this helped a bit
Area of the front and back faces = 2 [ (8.1 x 8.1) + (1/2 x 8.1 x 2.1 ] = 148.23 in²
Area of the right and left faces = 2 [ 11.8 x 8.1 ] = 191.16 in²
Area of the top = 2 [4.6 x 11.8] = 108.56 in²
Total Area = 148.23 in² + 191.16 in² + 108.56 in² = 447.95 in²
Answer: Theo will need to paint about 447.95 in².
Answer:
I think it's option B ...
