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4 years ago

Can you guys help me out with this one

Mathematics

2 answers:

creativ13 [48]4 years ago

6 0

X should equal 118 if I did the math correctly

ElenaW [278]4 years ago

6 0

Answer:

i think it is 118 but i may have done something wrong

Step-by-step explanation:

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Selena bought 3.75 pounds of meat for $4.64 per pound. What was the total cost of the meat

Contact [7]

$3.75 \times 4.64 = 17.40$

5 0

4 years ago

Guided Practice

Schach [20]

Answer:

Ah! Geometric sequences, Eh? Sucks I know....

Step-by-step explanation:

So first, we need to find the factor of this(been a while since I have done this)

$r=\frac{24}{48} =\frac{1}{2}$

So we found the relationship! Now we find the entire equation.

So we know the first term, 96, so let's use it!

$a_{n} =96*(\frac{1}{2})^{n-1}$

So there is the equation!

Now to find the 10th term.

$a_{n} =96*(\frac{1}{2})^{n-1}\\a_{10} =96*(\frac{1}{2})^{9}\\a_{10} =96*\frac{1}{2^{9} } \\a_{10}=0.1875$

There you have it!

Hope this Helps!

P.S. Stay Safe!

6 0

3 years ago

What is the value of the 4 in 2.704

tankabanditka [31]

The value of 2.704 is .004 because it is 3 spaces to the right of the decimal point.

8 0

3 years ago

An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20

expeople1 [14]

Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

$\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|$

From the table

$\sum f_i =149+x+y$

Here, n = 200

n/2 = 100

Lower Class Boundary of the median class, l=60

Frequency of the median class(f) =66

Cumulative Frequency before the median class, f=42+x

Class Width, h=10

$Median = l + \dfrac{\dfrac{n}{2} - c.f }{f} \times h$

$70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8$

200=149+x+y

200=149+8+y

y=200-(149+8)

y=43

Hence, the missing frequencies are x = 8 and y = 43.

8 0

3 years ago

Find cos (2 theta angle) if sin (theta angle) =4/5

nataly862011 [7]

Sin(theta) = 4/5, $cos^{2} (theta)=1-( \frac{4}{5})^{2} = 1 - \frac{16}{25} = \frac{9}{25}$ We will switch it to formula: $cos(2 theta)=cos^{2} (theta)-sin^{2} (theta)= \frac{9}{25} - \frac{16}{25}=- \frac{7}{25}$

5 0

4 years ago