For the first draw, if he has 9 marbles and 2 are green, the probability is 2/9. Without putting it back, 8 marbles are left, and he draws a red. Since there are 2 red of 8 marbles, the probability is 1/4. Now, multiply the two: 2/36 Simplify: 1/18 Hope this helps!
For the first marble chosen, the probability that the marble is green is 5/9.
After the first choice, since she didn't put it back, there are 8
marbles left, of which 2 are red. So the probability of the second one
being red is 2/8 = 1/4.
Since the question is asking the probability of BOTH events happening, you multiply the two probabilities.
So the answer is (5/9) * (1/4) = 5/36. hope this helps
