Answer:
482 km
63.94 degrees
Step-by-step explanation:
to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.
Cosine rule states that
C = 
where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060
solving now, we have
C = 
C = ![\sqrt{250000 + 90000 - [215000 cos(60) }]](https://tex.z-dn.net/?f=%5Csqrt%7B250000%20%2B%2090000%20-%20%5B215000%20%20%20cos%2860%29%20%20%7D%5D)
C = ![\sqrt{340000 - [215000 * 0.5 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B215000%20%2A%200.5%20%20%7D%5D)
C = ![\sqrt{340000 - [107500 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B107500%20%20%7D%5D)
C =
C = 482 km
The bearing can be gotten by using the Sine Rule.
= 
sina/500 = sin60/482
482 sina = 500 sin60
sina = 
sina = 0.8983
a = sin^-1(0.8983)
a = 63.94 degrees
Answer
0.22580645161
Step-by-step explanation:
you just have to do 4 3/7 in a calculator
Answer: 50653
37³ = (40 - 3)³ = 40³ - 3.40².3 + 3.40.3² - 3³
= 64000 - 14400 + 1080 - 27
= 50653
Step-by-step explanation:
Answer:
AC+ CD = ACD
X+1 + 2X + 2 = 30
3X+3 =30
3X=30–3
3X=27
X= 27/ 3
X= 9
I'm not sure of the solution, but I solved it according to a straight line (Line segment) .
I hope I helped you^_^