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3 years ago

So for the remaining angles

Mathematics

2 answers:

ivanzaharov [21]3 years ago

6 0

It’s solved by using the cosine rule

oksano4ka [1.4K]3 years ago

6 0

Answer:

∠BAC= 78.6° (1 d.p.)

∠ABC= 50.7°

∠ACB= 50.7°

Please see attached picture for full solution.

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The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope

yan [13]

Answer:

Slope of the line $PQ is -63.434948.$

Step-by-step explanation:

Given that,

The point $P(8,-3)$ lies on the curve $y=\frac{3}{7-x}$ .

If $Q$ is the point lies on $(x,\frac{3}{7-x} )$ .

To find:- Find the slope of line $PQ$ .

So,

The coordinates of point $Q$ when it lies on $(x,\frac{3}{7-x} )$

if $x=1$ then $y= \frac{3}{7-1} =\frac{3}{6} =\frac{1}{2}$

So, $Q$ ≡ $(1,\frac{1}{2} )$ and many points can be calculated by given Equation.

Using the formula when two points $(x_{1} ,y_{1} ) \& (x_{2}, y_{2} )$ .

$Slope=Tan\theta = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Then, substituting the coordinates we get,

$Slope = \frac{1-8}{\frac{1}{2}-(-3) }$

$Slope = \frac{-7}{\frac{1}{2}+3 } = \frac{-7}{\frac{7}{2} }$

$Slope = \frac{-14}{7}=-2$

$tan\theta=-2$ ⇒ $\theta = tan^{-1} (-2)$

$\theta= -63.434948$

Therefore,

Slope of the line $mPQ is -63.434948.$

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3 years ago

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liubo4ka [24]

Answer:

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Step-by-step explanation:

Wheel Rotates 15 times in 60 seconds

This implies that the wheel completes

15 × 360 degrees in 60 seconds

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In 1 second it Rotates 15× 360 / 60

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in 12 seconds , 12×90 = 1080°.

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3 years ago

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