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liq [111]
3 years ago
12

So for the remaining angles

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0
It’s solved by using the cosine rule
oksano4ka [1.4K]3 years ago
6 0

Answer:

∠BAC= 78.6° (1 d.p.)

∠ABC= 50.7°

∠ACB= 50.7°

Please see attached picture for full solution.

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A large high school offers AP Statistics and AP Calculus Among the seniors in this school 65% take AP Statistics, 45% take AP Ca
Igoryamba

Answer:

0.8

Step-by-step explanation:

P(AP statistics) = 65%

P(AP Calculus) = 45%

P(AP statistics n AP Calculus) = 30%

Probability of AP statistics or AP Calculus but not both :

Probability of event A or B :

P(AUB) = p(A) + p(B) - p(AnB)

P(AP statistics U AP Calculus) = P(AP statistics) + P(AP Calculus) - P(AP statistics n AP Calculus)

= 0.65 + 0.45 - 0.30

= 0.8

= 80%

4 0
3 years ago
Find the area of a circle with radius 7cm
uysha [10]
<span>153.94 is the answer. </span>
4 0
3 years ago
Read 2 more answers
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
I need help please and thanks
lakkis [162]

Answer:

the answer is associative

Step-by-step explanation:

3 0
3 years ago
The figure below shows a shaded region and a nonshaded region. Angles in the figure that appear to be right angles are right ang
serious [3.7K]
16 x 8 = 128 square feet (area of rectangle)

shaded:
8 x 2 = 16
10 x 1 = 10
1/2 (3)(10) = 15

total shaded area: 16+10+15 = 41 square feet
total non-shaded area = 128 - 41 = 87 square feet

answer

area of the shaded region = 41 square feet
area of the non - shaded region = 87 square feet
5 0
3 years ago
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