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3 years ago

So for the remaining angles

Mathematics

2 answers:

ivanzaharov [21]3 years ago

6 0

It’s solved by using the cosine rule

oksano4ka [1.4K]3 years ago

6 0

Answer:

∠BAC= 78.6° (1 d.p.)

∠ABC= 50.7°

∠ACB= 50.7°

Please see attached picture for full solution.

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Help me please for the brainliest answer

AveGali [126]

Answer with Step-by-step explanation:

$a) {n}^{2} + 3 \\ \\ n = 1 \\ {1}^{2} + 3 \\ 1 + 3 \\ = 4 \\ \\ n = 2 \\ {2}^{2} + 3 \\ 4 + 3 \\ = 7 \\ \\ n = 3 \\ {3}^{2} + 3 \\ 9 + 3 \\ = 12 \\ \\ n = 4 \\ {4}^{2} + 3 \\ 16 + 3 \\ = 19 \\ \\ n = 10 \\ {10}^{2} + 3 \\ 100 + 3 \\ = 103$

In this sequence,

1st term = 4

2nd term = 7

3rd term = 12

4th term = 19

10th term = 103

$b)2 {n}^{2} \\ \\ n = 1 \\ 2 \times {1}^{2} \\ 2 \times 1 \\ = 2 \\ \\ n = 2 \\ 2 \times {2}^{2} \\ 2 \times 4 \\ = 8 \\ \\ n = 3 \\ 2 \times {3}^{2} \\ 2 \times 9 \\ = 18 \\ \\ n = 4 \\ 2 \times {4}^{2} \\ 2 \times 16 \\ = 32 \\ \\ n = 10 \\ 2 \times {10}^{2} \\ 2 \times 100 \\ = 200$

in this sequence,

1st term = 2

2nd term =8

3rd term = 18

4th term =32

10th term = 200

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3 years ago

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Fittoniya [83]

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Step-by-step explanation:

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